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Show that the given function is not analytic at any point. \(f(z)=4 z-6 \bar{z}+3\)

Short Answer

Expert verified
The function \( f(z) = 4z - 6\bar{z} + 3 \) is not analytic at any point because it does not satisfy the Cauchy-Riemann equations.

Step by step solution

01

Define Analytic Function

A function is analytic at a point if it is differentiable at that point and also in a neighborhood around it. A complex function \( f(z) \) is differentiable if it satisfies the Cauchy-Riemann equations.
02

Express in terms of \(z\) and \(\bar{z}\)

Consider the given function: \( f(z) = 4z - 6\bar{z} + 3 \). Here, \( z = x + iy \) and \( \bar{z} = x - iy \). The function is expressed in terms of both \(z\) and its conjugate \(\bar{z}\), which is an indication to check for analyticity using Cauchy-Riemann equations.
03

Calculate Partial Derivatives

Express \( f(z) = 4z - 6\bar{z} + 3 \) in terms of \(x\) and \(y\): \[ f(z) = 4(x + iy) - 6(x - iy) + 3 = (4 - 6)x + (4i + 6i)y + 3 = -2x + 10iy + 3 \]. Then, calculate the partial derivatives: \( \frac{\partial u}{\partial x} = -2 \), \( \frac{\partial u}{\partial y} = 0 \), \( \frac{\partial v}{\partial x} = 0 \), \( \frac{\partial v}{\partial y} = 10 \). Here, \( u(x,y) = -2x + 3 \) and \( v(x,y) = 10y \).
04

Check Cauchy-Riemann Equations

The Cauchy-Riemann equations are \( \frac{\partial u}{\partial x} = \frac{\partial v}{\partial y} \) and \( \frac{\partial u}{\partial y} = -\frac{\partial v}{\partial x} \). Substituting the partial derivatives, we have: \( -2 = 10 \) and \( 0 = 0 \). The first equation does not hold, indicating that \( f(z) \) is not differentiable at any point.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Analytic Functions
In complex analysis, an **analytic function** is a beautiful concept that extends the idea of differentiability from real-valued functions to complex-valued functions. For a complex function to be analytic at a point, it must not only be differentiable at that point but also in a neighborhood surrounding it.
An analytic function can be infinitely differentiated and often expressed as a power series. This capability allows it to be approximated very accurately and studied thoroughly.
  • A function is called holomorphic if it is analytic at every point in its domain.
  • Analytic functions display properties such as conformality, meaning they preserve angles between curves.
To check if a function like the one given, \( f(z) = 4z - 6\bar{z} + 3 \), is analytic, we use the Cauchy-Riemann equations. If these equations don't hold, the function isn't analytic at any point, as demonstrated in the sample problem.
Cauchy-Riemann Equations
The **Cauchy-Riemann equations** are pivotal in determining whether a complex function is differentiable and therefore analytic. They provide a set of conditions that must be satisfied.
For a function \( f(z) = u(x, y) + iv(x, y) \), where \( z = x + iy \), these equations are:
  • \( \frac{\partial u}{\partial x} = \frac{\partial v}{\partial y} \)
  • \( \frac{\partial u}{\partial y} = -\frac{\partial v}{\partial x} \)
To be analytic at a point, both equations need to be satisfied simultaneously at that point and in a surrounding region. If any one fails, the function is non-analytic there.
This condition is why we derived the partial derivatives in the exercise. The exercise calculated them, showing that the equation \( -2 = 10 \) does not satisfy the Cauchy-Riemann condition. Therefore, demonstrating why the function is not analytic.
Complex Differentiation
In complex analysis, **complex differentiation** extends the notion of differentiating functions of a real variable into the realm of complex numbers. Unlike real differentiation, complex differentiation depends heavily on the function being analytic.
To perform the differentiation, high emphasis is placed on:
  • Ensuring that the function is locally linear, which essentially means, at small scales, it behaves like its linear approximation.
  • Verifying compliance with the Cauchy-Riemann equations, as previously discussed.
The existence of a complex derivative at a point implies differentiability in a neighborhood around that point, making this definition stricter than in real analysis.
This was illustrated by the given function, \( f(z) = 4z - 6\bar{z} + 3 \), which failed the complex differentiation test due to not satisfying the Cauchy-Riemann equations.

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