/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Use the rules of differentiation... [FREE SOLUTION] | 91Ó°ÊÓ

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Use the rules of differentiation to find \(f^{\prime}(z)\) for the given function. \(f(z)=\left(z^{4}-2 i z^{2}+z\right)^{10}\)

Short Answer

Expert verified
Apply the chain rule: \( f'(z) = 10 \cdot (z^4 - 2iz^2 + z)^9 \cdot (4z^3 - 4iz + 1) \).

Step by step solution

01

Identify the Differentiation Technique

The function given is in the form of a composite function, specifically a power of a polynomial. The most suitable rule for differentiation in this case is the chain rule.
02

Apply the Chain Rule

The chain rule states that if you have a function of the form \( (g(z))^n \), its derivative is \( n \cdot (g(z))^{n-1} \cdot g'(z) \). Here, \( g(z) = z^4 - 2iz^2 + z \) and \( n = 10 \). Therefore, the derivative will be \( 10 \cdot (g(z))^9 \cdot g'(z) \).
03

Differentiate the Inner Function

Find the derivative of the inner function \( g(z) = z^4 - 2iz^2 + z \). Using the power rule, the derivatives are: \( \frac{d}{dz} z^4 = 4z^3 \), \( \frac{d}{dz} (-2iz^2) = -4iz \), and \( \frac{d}{dz} z = 1 \). Combine these to get \( g'(z) = 4z^3 - 4iz + 1 \).
04

Substitute and Simplify

Substitute \( g(z) \) and \( g'(z) \) back into the chain rule expression. The derivative \( f'(z) \) is given by \( 10 \cdot (z^4 - 2iz^2 + z)^9 \cdot (4z^3 - 4iz + 1) \).
05

Write the Final Expression

The final derivative of the function is \( f'(z) = 10 \cdot (z^4 - 2iz^2 + z)^9 \cdot (4z^3 - 4iz + 1) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
The chain rule is an essential tool in calculus for finding derivatives of composite functions. A composite function is one in which one function is nested inside another. Simply put, the chain rule helps us differentiate functions that are composed of multiple layers.
For a function expressed as \( f(g(z)) \), the chain rule states that the derivative, \( f'(g(z)) \), can be found by multiplying the derivative of the outer function by the derivative of the inner function. In mathematical terms:
  • If \( f(z) = h(g(z)) \), then \( f'(z) = h'(g(z)) \cdot g'(z) \).
Using the chain rule simplifies the derivative process for complex functions, turning a daunting task into a step-by-step procedure. This rule is indispensable when working with functions raised to a power, like in this problem.
Composite Function
Composite functions can be a bit tricky because they involve plugging one function into another. It's like placing a puzzle piece inside another to form a complex image.
Given our problem, the composite function \( f(z) = (z^4 - 2iz^2 + z)^{10} \) involves an inner function \( g(z) = z^4 - 2iz^2 + z \) and an outer function, the power to 10. This means whatever happens inside \( g(z) \), it must be raised to the power of 10.
  • Understanding this layered structure is crucial for applying calculus rules like the chain rule effectively.
  • When you recognize the composite nature, it directly informs which operations and rules to follow when differentiating.
Breaking down functions into their components is a vital skill that makes calculus much more manageable.
Power Rule
The power rule is one of the simplest yet most powerful tools in differentiation. It allows us to easily find derivatives of polynomials.
Using the power rule can be boiled down to a simple formula: for any term \( x^n \), its derivative is \( n \cdot x^{n-1} \).
  • If \( g(z) = z^n \), then \( g'(z) = n \cdot z^{n-1} \).
  • Apply the power rule step-by-step to each term of the polynomial separately.
In the exercise, the power rule helps us find the derivative of the inner function \( g(z) = z^4 - 2iz^2 + z \) resulting in \( g'(z) = 4z^3 - 4iz + 1 \). Recognizing when and where to apply the power rule is vital for finding derivatives quickly and accurately.
Derivative of Polynomial
Finding the derivative of a polynomial is straightforward with rules like the power rule at our disposal. Polynomials are mathematical expressions consisting of variables and coefficients, raised to different powers.
Here's how you approach the derivative of a general polynomial:
  • Look at each term individually.
  • Apply the power rule to each term.
In the exercise, the polynomial \( g(z) = z^4 - 2iz^2 + z \) is differentiated to get \( g'(z) = 4z^3 - 4iz + 1 \).Polynomials are prevalent in mathematics, and gaining a strong understanding of their derivatives is foundational to mastering calculus concepts.

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Most popular questions from this chapter

Verify that the given function \(u\) is harmonic in an appropriate domain \(D .\) Find its harmonic conjugate \(v\) and find analytic function \(f(z)=u+i v\) satisfying the indicated condition. \(u(x, y)=x y+x+2 y ; f(2 i)=-1+5 i\)

The given analytic function \(f(z)=u+i v\) defines two families of level curves \(u(x, y)=c_{1}\) and \(v(x, y)=c_{2} .\) First use implicit differentiation to compute \(d y / d x\) for each family and then verify that the families are orthogonal. \(f(z)=x+\frac{x}{x^{2}+y^{2}}+i\left(y-\frac{y}{x^{2}+y^{2}}\right)\)

Suppose \(u(x, y)\) and \(v(x, y)\) are the real and imaginary parts of an analytic function \(f\). Can \(g(z)=v(x, y)+i u(x, y)\) be an analytic function? Discuss and defend your answer with sound mathematics.

The function \(\Omega(z)=\log _{e}\left|\frac{z+1}{z-1}\right|+i \operatorname{Arg}\left(\frac{z+1}{z-1}\right)\) is a complex potential of a two-dimensional electrostatic field. (a) Show that the equipotential curves \(\phi(x, y)=c_{1}\) and the lines of force \(\psi(x, y)=c_{1}\) are, respectively $$ \left(x-\operatorname{coth} c_{1}\right)^{2}+y^{2}=\operatorname{csch}^{2} c_{1} \text { and } x^{2}+\left(y+\cot c_{2}\right)^{2}=\csc ^{2} c_{2} $$ Observe that the equipotential curves and the lines of force are both families of circles. (b) The centers of the equipotential curves in part (a) are (coth \(c_{1}, 0\) ). Approximately, where are the centers located when \(c_{1} \rightarrow \infty ?\) When \(c_{1} \rightarrow-\infty ?\) Where are the centers located when \(c_{1} \rightarrow 0^{+} ?\) When \(c_{1} \rightarrow 0^{-} ?\) (c) Verify that each circular line of force passes through \(z=1\) and through \(z=-1\) (d) Use a CAS or graphing software to plot representative circles from each family on the same coordinate axes. If you use a CAS do not use the contour plot application.

Show that the given function is not analytic at any point. . \(f(z)=y+i x\)

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