Chapter 2: Problem 46
Find three sets in the complex plane that map onto the set \(\arg (w)=\pi\) under the mapping \(w=z^{3}\).
Short Answer
Expert verified
The sets are rays with angles \( \frac{\pi}{3} \), \( \pi \), and \( \frac{5\pi}{3} \).
Step by step solution
01
Understand the Problem
We are asked to find three sets in the complex plane that, when transformed by a given function, map onto a specific set given by the argument constraint \( \arg(w) = \pi \). The function in question is \( w = z^3 \), a mapping from \( z \) in the complex plane to \( w \).
02
Analyze the Target Set
The target set \( \arg(w) = \pi \) consists of all complex numbers with an argument of \( \pi \). This represents a line along the negative real axis. In polar coordinates, it is expressed as \( w = r(-1) \) where \( r \geq 0 \).
03
Consider the Mapping Function
The mapping is given by \( w = z^3 \). If \( z = re^{i\theta} \), then \( w = r^3 e^{i3\theta} \). We require \( 3\theta = \pi + 2k\pi \) for integers \( k \).
04
Solve for \( \theta \)
Solving \( 3\theta = \pi + 2k\pi \) gives \( \theta = \frac{\pi + 2k\pi}{3} \). For \( k = 0, 1, 2 \), these are the angles in the complex plane that will map to the argument \( \pi \) under the cube mapping.
05
Find the Sets
Substitute \( k \) to find \( \theta \):- For \( k = 0 \), \( \theta = \frac{\pi}{3} \).- For \( k = 1 \), \( \theta = \pi \).- For \( k = 2 \), \( \theta = \frac{5\pi}{3} \).These give the rays in the complex plane with angles \( \frac{\pi}{3}, \pi, \frac{5\pi}{3} \).
06
Define the Sets
Each set is a half-line originating from the origin: - Set 1: \( \theta = \frac{\pi}{3} \) corresponds to all \( z = re^{i\frac{\pi}{3}} \) for \( r \geq 0 \).- Set 2: \( \theta = \pi \) corresponds to all \( z = re^{i\pi} \) for \( r \geq 0 \).- Set 3: \( \theta = \frac{5\pi}{3} \) corresponds to all \( z = re^{i\frac{5\pi}{3}} \) for \( r \geq 0 \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Complex Plane
The complex plane is a two-dimensional plane used to represent complex numbers. It's like a regular Cartesian plane but instead of real numbers, we plot complex numbers with a real part and an imaginary part. Each complex number is of the form \( z = x + yi \), where \( x \) and \( y \) are real numbers, and \( i \) is the square root of \(-1\).
- Real Axis: The horizontal axis represents the real part of the complex number.
- Imaginary Axis: The vertical axis represents the imaginary part.
- Plotting a Point: A complex number \( z = 3 + 4i \) is represented as a point \( (3, 4) \) on the plane.
Argument of a Complex Number
The argument of a complex number is the angle made with the positive real axis. For a complex number \( z = re^{i\theta} \) expressed in polar form, this angle \( \theta \) is the argument of \( z \).
- Range: The argument usually lies in the range of \(-\pi \) to \( \pi \).
- Geometric Representation: It's the angle from the positive real axis to the line segment connecting the origin to \( z \).
- Unique Values: While the principal value lies within a specific range, any multiple of \( 2\pi \) can be added to get equivalent values, e.g., \( \theta + 2\pi k \).
Polar Coordinates
Polar coordinates offer a way to describe a complex number by its magnitude and direction, rather than its position in terms of axes. A complex number \( z \) in polar form is written as \( z = re^{i\theta} \) where:
- Magnitude: \( r = |z| \) is the distance from the origin.
- Argument: \( \theta \) is the angle the vector makes with the positive real axis.
Why Use Polar Form?
- Simplicity in Multiplication: Multiplying two complex numbers involves simply adding their arguments: \( z_1z_2 = r_1r_2e^{i(\theta_1 + \theta_2)} \).
- Simplicity in Powers and Roots: Calculating powers and roots is straightforward, as demonstrated with the function \( w = z^3 \), resulting in \( w = r^3e^{i3\theta} \).