/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 Find the natural domain of the g... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the natural domain of the given complex function \(f\).\(f(z)=\frac{i z}{|z-1|}\)

Short Answer

Expert verified
The domain is \( \{ z \in \mathbb{C} \, | \, z \neq 1 \} \).

Step by step solution

01

Understand the Function

The function given is a complex function defined as \( f(z) = \frac{i z}{|z - 1|} \). Here, \( i \) is the imaginary unit, and \( |z - 1| \) represents the modulus of the complex number \( z-1 \). The modulus \( |z - 1| \) is essentially the distance from the complex number \( z \) to the complex number \( 1 \).
02

Identify the Condition for Undefined Points

The function is undefined when the denominator is zero. Hence, \(|z - 1| = 0\). This occurs when \( z = 1 \) since the modulus of a complex number \( z \) is zero only when \( z = 0 \).
03

Determine the Natural Domain

The natural domain of the function \( f(z) \) is all complex numbers except where the function is undefined. Since the function is undefined at \( z = 1 \), the domain is the set of all complex numbers excluding \( z = 1 \).
04

Express the Natural Domain Mathematically

The natural domain of \( f(z) \) can be written in set notation as \( \{ z \in \mathbb{C} \, | \, z eq 1 \} \). This set includes every complex number except \( z = 1 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complex Functions
In the realm of complex analysis, complex functions form the backbone of numerous calculations and theories. A complex function involves a complex variable, typically denoted by \( z \), which is a number of the form \( z = x + yi \), where \( x \) and \( y \) are real numbers, and \( i \) is the imaginary unit with the property \( i^2 = -1 \). Complex functions map complex numbers to complex numbers, and they are expressed as \( f(z) = u(x, y) + iv(x, y) \). Here, \( u \) and \( v \) are real-valued functions of two variables \( x \) and \( y \).
  • Complex functions disrupt the simplicity of real functions by introducing the imaginary unit \( i \), which allows for a more profound exploration of mathematical phenomena.
  • The behavior of complex functions can be significantly different from real-valued functions, leading to intriguing properties like analytic continuation and complex conjugation.
To understand complex functions fully, one must become familiar with not only their algebraic form but also their geometric interpretation in the complex plane, often making the study of these functions both fascinating and multi-dimensional.
Natural Domain
In complex analysis, understanding the natural domain of a function is crucial for analyzing its behavior and correctly applying mathematical operations. The natural domain of a complex function is the set of all complex numbers \( z \) for which the function is defined. For rational functions, like \( f(z) = \frac{i z}{|z - 1|} \), the domain is restricted by the condition that the denominator must not be zero.
  • If the denominator becomes zero, the function is undefined at that point, as division by zero is nonexistent in mathematics.
  • For our function, \( f(z) \), it is undefined when \(|z - 1| = 0\). This holds true only when \( z = 1 \), as the modulus of \( z - 1 \) is zero only when \( z \) equals 1.
Therefore, the natural domain excludes \( z = 1 \), resulting in \( \{ z \in \mathbb{C} \mid z eq 1 \} \), a set capturing all complex numbers except where the function goes undefined. Identifying a function's natural domain is an essential step when working with complex functions, ensuring that all calculations are logically sound and mathematically valid.
Complex Modulus
The concept of complex modulus is a pivotal idea in the study of complex numbers. The modulus of a complex number \( z = x + yi \) is the distance from the origin in the complex plane, calculated as \( |z| = \sqrt{x^2 + y^2} \).
  • This measure is analogous to the absolute value for real numbers but extended into two dimensions to accommodate the imaginary part.
  • For the function \( f(z) = \frac{i z}{|z - 1|} \), the modulus \(|z - 1|\) essentially measures how far \( z \) is from the point \( 1 \) on the complex plane.
The traversal from the concept of the real number line to that of the complex plane expands the notion of distance, making the modulus a fundamental part of complex arithmetic. It not only determines the size or magnitude of a complex number but also plays a crucial role in defining other operations like the division of complex numbers, where understanding the modulus helps avoid undefined points as encountered in this exercise, ensuring that the computations stay within the permissible domain.

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Most popular questions from this chapter

Consider the function \(h(z)=\frac{2 i}{z}+1\) defined on the extended complex plane. (a) Using the fact that \(h\) is a composition of the reciprocal function \(f(z)=1 / z\) and the linear function \(g(z)=2 i z+1\), that is, \(h(z)=g(f(z))\), describe in words the action of the mapping \(w=h(z)\). (b) Determine the image of the line \(x=4\) under \(w=h(z)\). (c) Determine the image of the circle \(|z+2|=2\) under \(w=h(z)\).

Find the image of the given set under the principal square root mapping \(w=z^{1 / 2}\). Represent the mapping by drawing the set and its image.the ray \(\arg (z)=\frac{\pi}{4}\)

Find four sets in the complex plane that map onto the circle \(|w|=4\) under the mapping \(w=z^{4}\).

Groups of Isometries In this project we investigate the relationship between complex analysis and the Euclidean geometry of the Cartesian plane. The Euclidean distance between two points \(\left(x_{1}, y_{1}\right)\) and \(\left(x_{2}, y_{2}\right)\) in the Cartiesian plane is $$ d\left(\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right)\right)=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}} $$ Of course, if we consider the complex representations \(z_{1}=x_{1}+i y_{1}\) and \(z_{2}=\) \(x_{2}+i y_{2}\) of these points, then the Euclidean distance is given by the modulus $$ d\left(z_{1}, z_{2}\right)=\left|z_{2}-z_{1}\right| $$ A function from the plane to the plane that preserves the Euclidean distance between every pair of points is called a Euclidean isometry of the plane. In particular, a complex mapping \(w=f(z)\) is a Euclidean isometry of the plane if $$ \left|z_{2}-z_{1}\right|=\left|f\left(z_{1}\right)-f\left(z_{2}\right)\right| $$ for every pair of complex numbers \(z_{1}\) and \(z_{2}\).(a) Prove that every linear mapping of the form \(f(z)=a z+b\) where \(|a|=1\) is a Euclidean isometry. A group is an algebraic structure that occurs in many areas of mathematics. A group is a set \(G\) together with a special type of function \(*\) from \(G \times G\) to \(G\). The function \(*\) is called a binary operation on \(G\), and it is customary to use the notation \(a * b\) instead of \(*(a, b)\) to represent a value of \(* .\) We now give the formal definition of a group. A group is a set \(G\) together with a binary operation \(*\) on \(G\), which satisfies the following three properties: (i) for all elements \(a, b\), and \(c\) in \(G, a *(b * c)=(a * b) * c\),(b) Prove that composition of functions is a binary operation on Isom \(_{+}(\mathbf{E})\). That is, prove that if \(f\) and \(g\) are functions in Isom \(_{+}(\mathbf{E})\), then the function \(f \circ g\) defined by \(f \circ g(z)=f(g(z))\) is an element in Isom \(_{+}(\mathbf{E})\). (c) Prove that the set Isom \(_{+}(\mathbf{E})\) with composition satisfies property \((i)\) of a group. (d) Prove that the set \(\operatorname{Isom}_{+}(\mathbf{E})\) with composition satisfies property \((i i)\) of a group. That is, show that there exists a function \(e\) in Isom \(_{+}(\mathbf{E})\) such that \(e \circ f=f \circ e=f\) for all functions \(f\) in Isom \(_{+}(\mathbf{E})\). (e) Prove that the set Isom \(_{+}(\mathbf{E})\) with composition satisfies property \((i i i)\) of a group.

Find the image of the given set under the reciprocal mapping \(w=1 / z\) on the extended complex plane.the circle \(\left|z+\frac{1}{4}\right|=\frac{1}{4}\)

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