Chapter 2: Problem 23
Use parametrizations to find the image, \(C^{\prime}\), of the curve \(C\) under the given complex mapping \(w=f(z)\).\(f(z)=1 / z ; C\) is the circle \(|z|=2\)
Short Answer
Expert verified
The image is a circle of radius \( \frac{1}{2} \).
Step by step solution
01
Understanding the function and curve
We are given a complex function \( f(z) = \frac{1}{z} \) and a curve \( C \) which is a circle defined by \( |z| = 2 \). This means every point \( z \) on \( C \) satisfies the equation \( |z| = 2 \).
02
Parametrize the given curve
We can parametrize the circle \( |z| = 2 \) using the equation \( z(t) = 2e^{i\theta} \) where \( 0 \leq \theta < 2\pi \). This describes a circle with a radius of 2 centered at the origin in the complex plane.
03
Apply the mapping to the parametrization
Using the mapping \( w = \frac{1}{z} \), substitute the parametrization from Step 2: \[ w(t) = \frac{1}{2e^{i\theta}} = \frac{1}{2}e^{-i\theta}. \] This simplifies the image of every point on the circle under the mapping.
04
Determine the image curve
The expression \( w(t) = \frac{1}{2}e^{-i\theta} \) describes another circle, but this time with a radius of \( \frac{1}{2} \) centered at the origin. As \( \theta \) varies from \( 0 \) to \( 2\pi \), the entire circle is traced out.
05
Conclusion about the image
Therefore, the image \( C' \) of the circle \( C \) under the mapping \( f(z) = \frac{1}{z} \) is another circle defined by \( |w| = \frac{1}{2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parametrization
In the realm of complex analysis, parametrization is a method used to express a curve in terms of a single or multiple parameters, which allows us to analyze and map the curve easily in the complex plane. For example, given a circle defined by its radius and center in the complex plane, parametrization helps describe every point on that circle in terms of an angle, denoted as \( \theta \).
- For a circle with radius \( r \) centered at the origin, each point \( z \) on the circle can be expressed as \( z(t) = re^{i\theta} \), where \( 0 \leq \theta < 2\pi \).
- Here, \( e^{i\theta} \) represents a point on the unit circle in the complex plane, which is then scaled by \( r \) to adjust the radius.
Complex Function Mapping
Complex function mapping involves transforming each point in the complex plane through a defined complex function, resulting in a new image of those points. This is crucial in complex analysis to study how complex functions behave under different inputs.
- The function \( f(z) = \frac{1}{z} \) is a well-known example of a complex mapping, often referred to as an inversion in the complex plane. It maps each non-zero point \( z \) to its reciprocal.
- When applied to a parametrized curve, like a circle, the function can entirely change the geometry of that curve, as each point on the original circle is mapped to a new location in the complex plane.
Circle in Complex Plane
A circle in the complex plane is more than just a geometric shape. It represents a set of points equidistant from the center, often described using its radius and center coordinates. In complex analysis, circles are frequently explored through their algebraic representations like \( |z| = r \), where \( r \) denotes the radius.
- The notation \( |z| = r \) means the modulus (or absolute value) of the complex number \( z \) is constant and equal to the radius \( r \).
- In the context of mapping, a circle can be transformed into another geometric shape, such as another circle with a different radius or even non-circular paths, depending on the properties of the mapping function.