Chapter 2: Problem 18
Plot the parametric curve \(C\) given by \(z(t)\) and describe the curve in words, (b) find a parametrization of the image, \(C^{\prime}\), of \(C\) under the given complex mapping \(w=f(z)\), and (c) plot \(C^{\prime}\) and describe this curve in words.\(z(t)=i+e^{i t}, 0 \leq t \leq \pi ; f(z)=(z-i)^{3}\)
Short Answer
Step by step solution
Identify and Rewrite Parametric Form
Plot Parametric Curve C
Parametrize Image Under Mapping
Plot Image Curve C'
Interpretation of the Curves
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parametric Curve
To better visualize this, we can rewrite \(e^{it}\) using its trigonometric form: \(e^{it} = \cos(t) + i\sin(t)\). Hence, the curve becomes \(z(t) = \cos(t) + (1+\sin(t))i\).
This means the real part of \(z(t)\) is \(\cos(t)\) and the imaginary part is \(1 + \sin(t)\), forming a semicircle. In essence, the parametric curve here represents a movement from the point \((0, 1)\) at \(t = 0\), tracing a semicircle, and ending back below at \(t = \pi\) in the complex plane.
Complex Mapping
To understand this, we replace \(z\) with our parametric equation \(z(t) = i + e^{it}\), then under the mapping \(w = f(z) = (z-i)^3\), substitute to get \(w(t) = (e^{it})^3 = e^{3it}\).
Through this mapping, the initial curve transforms by scaling and rotating according to the formula. It effectively stretches the angle threefold, compressing the semicircle into a shorter angular distance. Thus, complex mapping can drastically change the shape and size of the curve being transformed, as seen with the effect on curve \(C'\).
Complex Plane
For the curve \(z(t) = i + e^{it}\), we interpret its behavior on this plane. The curve begins at \(1i\) (purely imaginary, since the cosine term vanishes at \(t = 0\)) and moves as \(t\) increases, drawing a semicircle.
The image curve \(C'\) described by \(w(t) = e^{3it}\) is similarly plotted in the complex plane, illustrating how the mapping \((z-i)^3\) changes the shape. This underscores how the complex plane is a crucial tool in visualizing the transformations complex numbers undergo.
Exponential Form
This form is instrumental in revealing the circular nature of the movement as \(e^{it}\) traces a unit circle in the complex plane. Additionally, the mapping ensures that the function could be expressed as \((e^{it})^3 = e^{3it}\).
Using exponential form aids in simplifying expressions, calculating powers of complex numbers easily, and understanding rotational symmetries, making it indispensable in both theoretical and applied complex analysis.