/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Sketch the set \(S\) of points i... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Sketch the set \(S\) of points in the complex plane satisfying the given inequality. Determine whether the set is (a) open, (b) closed, (c) a domain, (d) bounded, or (e) connected. $$ 2 \leq|z-3+4 i| \leq 5 $$

Short Answer

Expert verified
The set is closed, bounded, and connected, but not open or a domain.

Step by step solution

01

Understand the inequality

The inequality \(2 \leq |z - 3 + 4i| \leq 5\) represents a set of all complex numbers \(z\) such that the magnitude of \(z - (3 - 4i)\) is between 2 and 5. This can be visualized as an annular region (a ring) in the complex plane centered at the point \((3, -4)\) with inner radius 2 and outer radius 5.
02

Sketch the set in the complex plane

To sketch the set, first draw the center point \((3, -4)\) on the complex plane. Next, draw a circle of radius 2 around this center. Then, draw another larger circle with radius 5 around the same center point. Shade the region between these two circles. This shaded area is your set \(S\).
03

Determine if the set is open

A set is considered open if, for every point inside the set, there exists a small enough neighborhood around that point which is entirely contained within the set. In this case, the boundary points of the annulus (where \(|z - 3 + 4i| = 2\) and \(|z - 3 + 4i| = 5\)) are included in the set, hence it is not open.
04

Determine if the set is closed

A set is closed if it contains all its boundary points. Here, the set includes the boundary circles where \(|z - 3 + 4i| = 2\) and \(|z - 3 + 4i| = 5\). Therefore, the set is closed.
05

Determine if the set is a domain

A domain is an open and connected set. Since our set is not open, it cannot be a domain. Therefore, the set is not a domain.
06

Determine if the set is bounded

A set is bounded if it can be contained within some circle with finite radius. Since the set is an annular region between two circles with finite radii (2 and 5), it is indeed bounded.
07

Determine if the set is connected

A set is connected if it is all "in one piece" and there are no separate parts. The annular region forms a single piece without any disconnections within the region itself, so it is connected.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Open and Closed Sets
In complex analysis, sets can be classified as open or closed based on their boundary properties. An **open set** means that for each point within it, you can find a small neighborhood around that point which entirely fits inside the set, excluding boundary points.
On the other hand, a **closed set** includes its boundary points. Consider the annular region defined by the inequality \(2 \leq |z - 3 + 4i| \leq 5\). This set includes the circles where \(|z - 3 + 4i| = 2\) and \(|z - 3 + 4i| = 5\), hence it is closed.

Understanding these concepts helps in visualizing how sets behave in the complex plane. Continuous geometric stretches that incorporate boundary points often correspond to closed sets. Open sets, in contrast, would lack such boundary inclusions, giving a different character to their geometric depiction.
Domain in Complex Analysis
In complex analysis, a **domain** is an important concept referring to sets that are both open and connected.
Since a domain must satisfy both conditions, understanding each is crucial. The set expressed by \(2 \leq |z - 3 + 4i| \leq 5\) is not a domain since it is closed, as discussed earlier.
  • An open set doesn't include its boundary, giving a flexible structure.
  • A connected set is one that’s formed as a single piece.
Since our set doesn't meet the open criterion, despite being connected, it cannot qualify as a domain. Recognizing domains helps frame analytic contexts, especially when considering functions that are analytic over such regions.
Bounded Sets
In the realm of complex numbers, a **bounded set** can be thought of as a set that can be circumvented by a large enough circle of finite radius.
The set defined by \(2 \leq |z - 3 + 4i| \leq 5\) is an annular region enclosed between two such circles. With inner and outer radii of 2 and 5 respectively, this set clearly satisfies the bounded condition.

Understanding boundedness conveys the size and limits of a set in the complex plane. It ensures that the set doesn’t stretch out to infinity in any direction. Bounded sets are crucial in complex analysis, particularly when discussing convergence and limits within a set.
Connected Sets
A **connected set** in complex analysis is like a single piece with no separations.
The set given by \(2 \leq |z - 3 + 4i| \leq 5\) forms an annular or ring-like shape, which is connected because it's continuously "in one piece."
  • Connectedness ensures no isolated parts or breakages within the set.
  • Supports continuity of functions defined over it.
Visualizing connected sets aids in understanding complex pathways and function continuity. In a connected complex region, you can traverse from any point to any other without leaving the set, illustrating crucial aspects of network-like continuity.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Sketch the graph of the given equation in the complex plane. $$ |z+3 i|=2 $$

Sketch the graph of the given equation in the complex plane. $$ |z+2+2 i|=2 $$

Sketch the graph of the given equation in the complex plane. $$ \operatorname{Im}(z)=-2 $$

In this project we assume that you have either had some experience with matrices or are willing to learn something about them. Certain complex matrices, that is, matrices whose entries are complex numbers, are important in applied mathematics. An \(n \times n\) complex matrix \(A\) is said to be: Here the symbol \(\bar{A}\) means the conjugate of the matrix \(A\), which is the matrix obtained by taking the conjugate of each entry of \(A . \bar{A}^{T}\) is then the transpose of \(\bar{A}\), which is the matrix obtained by interchanging the rows with the columns. The negative \(-A\) is the matrix formed by negating all the entries of \(A ;\) the matrix \(A^{-1}\) is the multiplicative inverse of \(A\) (a) Which of the following matrices are Hermitian, skew-Hermitian, or unitary? $$ \begin{aligned} &A=\left(\begin{array}{ccc} 3 i & 10 & -10-2 i \\ -10 & 0 & 4+i \\ 10-2 i & -4+i & -5 i \end{array}\right) \\ &B=\left(\begin{array}{ccc} 1 & 0 & 0 \\ 0 & \frac{2+i}{\sqrt{10}} & \frac{-2+i}{\sqrt{10}} \\ 0 & \frac{2+i}{\sqrt{10}} & \frac{2-i}{\sqrt{10}} \end{array}\right) \\ &C=\left(\begin{array}{ccc} 2 & 1+7 i & -6+2 i \\ 1-7 i & 4 & 1+i \\ -6-2 i & 1-i & 0 \end{array}\right) \end{aligned} $$ (b) What can be said about the entries on the main diagonal of a Hermitian matrix? Prove your assertion. (c) What can be said about the entries on the main diagonal of a skewHermitian matrix? Prove your assertion. (d) Prove that the eigenvalues of a Hermitian matrix are real. (e) Prove that the eigenvalues of a skew-Hermitian matrix are either pure imaginary or zero. (f) Prove that the eigenvalues of unitary matrix are unimodular; that is, \(|\lambda|=1\). Describe where these eigenvalues are located in the complex plane. (g) Prove that the modulus of a unitary matrix is one, that is, \(|\operatorname{det} A|=1\). (h) Do some additional reading and find an application of each of these types of matrices. (i) What are the real analogues of these three matrices?

Use de Moivre's formula (10) with \(n=2\) to find trigonometric identities for \(\cos 2 \theta\) and \(\sin 2 \theta\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.