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91Ó°ÊÓ

(i) If \(H\) is a subgroup of \(G\) and if \(x \in H\), prove that $$ C_{H}(x)=H \cap C_{G}(x) $$ (ii) If \(H\) is a subgroup of index 2 in a finite group \(G\) and if \(x \in H\), prove that either \(\left|x^{H}\right|=\left|x^{G}\right|\) or \(\left|x^{H}\right|=\frac{1}{2}\left|x^{G}\right|\), where \(x^{H}\) is the conjugacy class of \(x\) in \(H\).

Short Answer

Expert verified
For part (i), \(C_H(x) = H \cap C_G(x)\). For part (ii), \(|x^H| = |x^G|\) or \(|x^H| = \frac{1}{2}|x^G|\).

Step by step solution

01

Title - Definitions and Setup for Part (i)

Define the centralizers of an element in a group. For a group element \(x\), the centralizer of \(x\) in a group \(G\) is defined as \(C_G(x) = \{g \, | \, g \, \text{in} \, G, gx = xg\}\). Similarly, \(C_H(x)\) is defined in the subgroup \(H\).
02

- Proving Inclusion \(C_H(x) \subseteq H \cap C_G(x)\)

Since \(H\) is a subgroup of \(G\) and \(x \in H\), any \(h \in C_H(x)\) must be in \(H\) by definition. Additionally, since \(h \in H\) commutes with \(x\), it must also be in \(C_G(x)\). Thus, \(h \in H \cap C_G(x)\), proving that \(C_H(x) \subseteq H \cap C_G(x)\).
03

- Proving Inclusion \(H \cap C_G(x) \subseteq C_H(x)\)

Conversely, if \(h \in H \cap C_G(x)\), then \(h \in H\) and \(h \in C_G(x)\). Since \(h \in C_G(x)\), \(h\) must commute with \(x\), and because \(h \in H\), \(h \in C_H(x)\). Thus, \(H \cap C_G(x) \subseteq C_H(x)\).
04

- Concluding Part (i)

Therefore, \(C_H(x) = H \cap C_G(x)\) by proving both inclusions.
05

Title - Definitions and Setup for Part (ii)

Let \(H\) be a subgroup of index 2 in a finite group \(G\) and let \(x \in H\). The conjugacy class of \(x\) in \(H\) is denoted as \(x^H\) consisting of elements \(hxh^{-1}\) for \(h \in H\). Similarly, for \(G\), \(x^G\) consists of elements \(gxg^{-1}\) for \(g \in G\).
06

- Using the Index Property

Since \(H\) is of index 2 in \(G\), there are only two cosets of \(H\) in \(G\): \(H\) and \(G \setminus H\). For any \(x \in H\), \(x \in x^H\subseteq x^G\).
07

- Counting Conjugates

The size of the conjugacy class \(|x^H|\) in \(H\) can either be equal to the size of the conjugacy class \(|x^G|\) in \(G\), implying that all conjugates in \(G\) are already in \(H\), or half of \(|x^G|\), implying that exactly half of the conjugates in \(G\) are in \(H\). Thus, \(|x^H| = |x^G|\) or \(|x^H| = \frac{1}{2}|x^G|\).
08

- Concluding Part (ii)

Therefore, either \(|x^H| = |x^G|\) or \(|x^H| = \frac{1}{2}|x^G|\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Subgroup
A subgroup is a smaller group formed within a larger group, maintaining the structure and properties of the original group. Specifically, a subset of a group G is a subgroup if it is itself a group under the same operation defined on G. To be a subgroup, the set must satisfy three conditions:

  • Closure: For any elements a and b in the subgroup, the product ab is also in the subgroup.
  • Identity: The subgroup contains the identity element of G.
  • Inverses: For every element a in the subgroup, its inverse a-1 is also in the subgroup.
The notation H ≤ G denotes that H is a subgroup of G. For example, the set of all even integers under addition is a subgroup of the set of all integers.
Centralizer
The centralizer of an element in a group is the set of all elements in the group that commute with that element. Formally, the centralizer of an element x in a group G is defined as:

\[C_G(x) = \{ g \in G \; | \; gx = xg \}\]

This means that for every element g in C_G(x), the product of g and x is the same regardless of the order of multiplication. The concept of a centralizer helps to identify the elements that 'commute' with a particular element within the group.

In the context of the given exercise, if H is a subgroup of G, the centralizer of x in H, denoted C_H(x), consists of elements in H that commute with x. The exercise shows how to relate this set to the intersection of H and the centralizer of x in G, written as C_H(x) = H ∩ C_G(x).
Conjugacy Class
A conjugacy class of an element in a group is the set of elements that can be transformed into one another by conjugation. Conjugation involves an element g in the group, and it transforms an element x into gxg-1.

For a group G and an element x in G, the conjugacy class of x is denoted by xG, and it is:

\[x^G = \{ gxg^{-1} \; | \; g \in G \}\]

This means all elements that are 'similar' to x by the group operation are in the same conjugacy class. The size of a conjugacy class is an important aspect because it depicts how many unique elements can be formed through conjugation.

In the exercise, the conjugacy class xH in a subgroup H of index 2 in G has a size that is either equal to or half the size of the conjugacy class xG in the full group G. This result comes from the limited number of cosets of H in G and how conjugates partition accordingly.
Index of a Subgroup
The index of a subgroup H in a group G is the number of distinct cosets of H in G. A coset of H in G is a set formed by multiplying all elements of H by a particular element from G.

Mathematically, the index is defined as:

\[|G : H| = \text{Number of distinct cosets of H in G}\]

For instance, if H has index 2 in G, then there are exactly two cosets: H and G \ H. This situation often arises in the exercise when considering how elements and their properties distribute across the cosets.

In part (ii) of the exercise, we demonstrated that if H is a subgroup of index 2, then a given element x's conjugacy class in H either retains the total size from G or reduces to half in size, reflecting the subgroup's distinct characteristics.

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