Chapter 36: Problem 5
Find all Sylow 3 -subgroups of \(S_{4}\) and demonstrate that they are all conjugate.
Short Answer
Expert verified
The Sylow 3-subgroups of \(S_4\) are \( \langle (123) \rangle, \langle (124) \rangle, \langle (134) \rangle, \langle (234) \rangle \); all are conjugate.
Step by step solution
01
Determine the Order of the Group
The symmetric group on four elements, denoted as \(S_4\), has an order given by the factorial of the number of elements, i.e., \(\lvert S_4 \rvert = 4! = 24\).
02
Apply Sylow's Theorems to Find the Number of Sylow 3-Subgroups
By Sylow’s theorems, the number of 3-subgroups, denoted by \(n_3\), must satisfy two conditions: it must divide the order of \(S_4\) (24) and be congruent to 1 mod 3. Therefore, \(n_3\) could be 1 or 4.
03
Determine Feasibility of Each \(n_3\) Option
Since no single Sylow 3-subgroup contains all 3-cycles in \(S_4\), \(n_3 = 1\) would imply all such 3-cycles are in the same subgroup which contradicts since \(S_4\) has 8 such 3-cycles. Hence, \(n_3 = 4\).
04
Identify Sylow 3-Subgroups
Each Sylow 3-subgroup of \(S_4\) is generated by a 3-cycle. For instance, take \(H_1 = \langle (123) \rangle\), \(H_2 = \langle (124) \rangle\), \(H_3 = \langle (134) \rangle\), and \(H_4 = \langle (234) \rangle\). These are 3-cycle subgroups and indeed there are 4 of them.
05
Prove Conjugacy of These Subgroups
If two Sylow subgroups are conjugate in a group, there exists some element in the group that can map one subgroup to the other by conjugation. Take \((12)(34) \in S_4\), then \((12)(34)(123)(12)(34) = (124)\), making \(H_1\) conjugate to \(H_2\). One can find similar elements for other subgroup pairs, thus showing all are conjugate.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sylow 3-subgroups
A Sylow 3-subgroup is a specific type of subgroup determined by Sylow's theorems, tailored for applications involving group theory. These subgroups are crucial when identifying the structure within larger groups. To understand Sylow 3-subgroups, one starts by considering Sylow's theorems which offer a way to break down groups by their prime factors. In our case, the symmetric group \( S_4 \) has an order of 24, which factors as \( 2^3 \times 3^1 \). The number \( n_3 \) representing the Sylow 3-subgroups must adhere to two conditions:
\( n_3 \) divides 24 and \( n_3 \equiv 1 \pmod{3} \). Thus, \( n_3 \) could either be 1 or 4. By examining the symmetric group, it becomes evident that \( n_3 \) has to be 4, demarcating the presence of multiple Sylow 3-subgroups. Endorsed by this fact, we can distinctly identify four different Sylow 3-subgroups within \( S_4 \).
\( n_3 \) divides 24 and \( n_3 \equiv 1 \pmod{3} \). Thus, \( n_3 \) could either be 1 or 4. By examining the symmetric group, it becomes evident that \( n_3 \) has to be 4, demarcating the presence of multiple Sylow 3-subgroups. Endorsed by this fact, we can distinctly identify four different Sylow 3-subgroups within \( S_4 \).
symmetric group S4
The symmetric group \( S_4 \) is the group of all permutations on four elements, a fundamental concept in the realm of group theory. This group is vastly intriguing due to its structure and properties, making it a rich playground for understanding symmetry and permutations. The order of the group, which is 24, makes it a manageable yet complex enough entity to study various subgroup configurations.
- The identity element is present, performing no changes on the set.
- All possible transpositions, or swaps, of any two elements are present.
- More complex permutations are included, such as 3-cycles and 4-cycles.
3-cycles
In permutation groups, a 3-cycle is a particular permutation involving three elements, while holding others constant. It is denoted in cycle notation such as \((123)\), demonstrating that element 1 moves to the position of element 2, 2 to the position of 3, and 3 back to the position of 1. The power of 3-cycles lies in their ability to restructure parts of a group efficiently.In any examination of a group like \( S_4 \), identifying all possible 3-cycles becomes important because:
- They are generators of certain types of subgroups, such as Sylow 3-subgroups.
- The composition of these cycles determines how elements relate to one another.
- They are symmetric transformations conveying certain group properties.
group conjugation
Conjugation is a crucial operation in group theory, illustrating how subgroups can be transformed within a group. To conjugate one element by another, you essentially reposition elements according to the chosen conjugating element. Within \( S_4 \), any two Sylow 3-subgroups are considered conjugate if one can be shifted into another using elements from \( S_4 \).Suppose you have two subgroups \( H_1 = \langle (123) \rangle \) and \( H_2 = \langle (124) \rangle \). By selecting an appropriate conjugating element, such as \((12)(34)\), you can show:
- \((12)(34)(123)(12)(34) = (124)\), converting one subgroup into another.
- This process exemplifies how all Sylow 3-subgroups of \( S_4 \) are conjugate, pointing to their symmetry.