Chapter 31: Problem 27
\text { Prove in detail that } Q(\sqrt{3}+\sqrt{7})=Q(\sqrt{3}, \sqrt{7}) \text {. }
Short Answer
Expert verified
The fields \(Q(\sqrt{3}+\sqrt{7})\) and \(Q(\sqrt{3}, \sqrt{7})\) are the same.
Step by step solution
01
Understand the Sets
Identify the field extensions involved. The problem is asking us to prove that the field generated by \( \sqrt{3} + \sqrt{7} \) over \( \mathbb{Q} \) is the same as the field generated by \( \sqrt{3} \) and \( \sqrt{7} \). This means showing that both fields include the same elements.
02
Express in Terms of Radicals
Start by expressing \( \sqrt{3} + \sqrt{7} \) in terms of its radical components over \( \mathbb{Q} \). Consider these as elements in \( \mathbb{Q}(\sqrt{3}, \sqrt{7}) \). Both \( \sqrt{3} \) and \( \sqrt{7} \) are in this field by definition.
03
Show Inclusion of Radicals
Demonstrate that \( \sqrt{3} \) and \( \sqrt{7} \) can be individually expressed in the field \( \mathbb{Q}(\sqrt{3}+\sqrt{7}) \). For this, compute: \( (\sqrt{3}+\sqrt{7})^2 = 3 + 7 + 2 \sqrt{21} = 10 + 2 \sqrt{21} \). Subtract 10 and divide by 2 to isolate \( \sqrt{21} \). Next, use: \( (\sqrt{3}+\sqrt{21})^2 = 3+21+2\sqrt{63} \) to extract \( \sqrt{3} \), and \( (\sqrt{7}+\sqrt{21})^2 = 7+21+2\sqrt{147} \) to extract \( \sqrt{7} \).
04
Verify Full Field Composition
Verify that these radicals \( \sqrt{3} \) and \( \sqrt{7} \) can combine in reverse to recreate any element in \( \mathbb{Q}(\sqrt{3}, \sqrt{7}) \). Since both radicals are extracted, any polynomial in \( \sqrt{3} \) and \( \sqrt{7} \) is similarly recreated.
05
Conclusion Proven
Since both \( \sqrt{3} \) and \( \sqrt{7} \) are contained in \( \mathbb{Q}(\sqrt{3}+\sqrt{7}) \), ensure backward compatibility by showing each generates the entire field, confirming \( \mathbb{Q}(\sqrt{3}+\sqrt{7}) = \mathbb{Q}(\sqrt{3},\sqrt{7}) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Field Extensions
A field extension is a bigger field containing a smaller field. Imagine fields as collections of numbers that work well under addition, subtraction, multiplication, and division.
When we extend a field, we add more numbers but still keep the rules intact. For instance, if we have a field like \( \mathbb{Q} \), the field of rational numbers, we can "extend" it by adding a number like \( \sqrt{3} \). This means that \( \sqrt{3} \) becomes part of the new field, and we call this \( \mathbb{Q}(\sqrt{3}) \).
Field extensions can include new numbers and all the numbers you get by doing something to these new numbers with things in the original field.
When we extend a field, we add more numbers but still keep the rules intact. For instance, if we have a field like \( \mathbb{Q} \), the field of rational numbers, we can "extend" it by adding a number like \( \sqrt{3} \). This means that \( \sqrt{3} \) becomes part of the new field, and we call this \( \mathbb{Q}(\sqrt{3}) \).
Field extensions can include new numbers and all the numbers you get by doing something to these new numbers with things in the original field.
- Start with a base field, e.g., \( \mathbb{Q} \).
- Add a new element, e.g., \( \sqrt{3} \).
- Form a larger field with this new element and the original field.
Radical Extensions
A radical extension is a special type of field extension. It involves adding roots like square roots, cube roots, etc., to a field.
When we talk about radical extensions, we're focusing on what happens when you add elements like \( \sqrt{3} \) or \( \sqrt{7} \) to an existing set of numbers.
The field \( \mathbb{Q}(\sqrt{3}, \sqrt{7}) \) is a radical extension of \( \mathbb{Q} \) because it includes the square roots of 3 and 7, both of which were not part of the original field \( \mathbb{Q} \).
To create a radical extension, you are extending a field by including all combinations and derivations of these roots:
When we talk about radical extensions, we're focusing on what happens when you add elements like \( \sqrt{3} \) or \( \sqrt{7} \) to an existing set of numbers.
The field \( \mathbb{Q}(\sqrt{3}, \sqrt{7}) \) is a radical extension of \( \mathbb{Q} \) because it includes the square roots of 3 and 7, both of which were not part of the original field \( \mathbb{Q} \).
To create a radical extension, you are extending a field by including all combinations and derivations of these roots:
- Consider any base field, like \( \mathbb{Q} \).
- Add elements defined by radicals, such as \( \sqrt{3} \).
- Include all results of operations like multiplication and division involving these added elements.
Polynomial Expressions
Polynomial expressions are algebraic expressions involving sums of powers of a variable, in a formula like \( ax^n + bx^{n-1} + \ldots + c \).
They are powerful tools because they let us express complex numbers and operations in simplified forms. For example, \( (\sqrt{3} + \sqrt{7})^2 = 10 + 2\sqrt{21} \), which is just a polynomial expression.
They are powerful tools because they let us express complex numbers and operations in simplified forms. For example, \( (\sqrt{3} + \sqrt{7})^2 = 10 + 2\sqrt{21} \), which is just a polynomial expression.
- This exercise shows how polynomial expressions can be used to transform expressions back into their individual radical components.
- In essence, polynomial manipulations help in revealing how different field elements relate to each other.
- Working with polynomial expressions ensures that even complicated radicals can be traced back to known field elements.