Chapter 20: Problem 27
Show that 1 and \(p-1\) are the only elements of the field \(Z_{p}\) that are their own multiplicative inverse.
Short Answer
Expert verified
Only 1 and \(p-1\) are their own inverses in \(\mathbb{Z}_p\).
Step by step solution
01
Definition of Multiplicative Inverse in a Field
In a field, an element's multiplicative inverse is another element such that their product is equal to 1. Given a field \(\mathbb{Z}_p\), any element \(a\) for which \(a \cdot a = 1 \mod p\) is termed its own inverse.
02
Analyze Condition for Equation
For an element \(a\) to be its own inverse, the equation \(a^2 \equiv 1 \mod p\) must hold true. This simplifies to \(a^2 - 1 \equiv 0 \mod p\), or \((a-1)(a+1) \equiv 0 \mod p\).
03
Factor Solution in Field \(\mathbb{Z}_p\)
In a field \(\mathbb{Z}_p\), a product is congruent to zero mod \(p\) when at least one of the factors is congruent to zero mod \(p\). Thus, it requires that either \(a - 1 \equiv 0 \mod p\) or \(a + 1 \equiv 0 \mod p\).
04
Solve for \(a\)
The equation \(a - 1 \equiv 0 \mod p\) gives \(a \equiv 1 \mod p\). Similarly, \(a + 1 \equiv 0 \mod p\) gives \(a \equiv -1 \equiv p-1 \mod p\).
05
Conclusion
The solutions to \(a^2 \equiv 1 \mod p\) in \(\mathbb{Z}_p\) are \(a = 1\) and \(a = p-1\). Thus, only 1 and \(p-1\) can serve as their own multiplicative inverses in \(\mathbb{Z}_p\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Multiplicative Inverse
In mathematics, particularly in the study of fields, the multiplicative inverse of a number is a concept you might encounter frequently. The multiplicative inverse, sometimes called the reciprocal, of a number is simply another number that multiplies with it to yield the number one. Consider the number 5. Its multiplicative inverse is \( \frac{1}{5} \) since \( 5 \times \frac{1}{5} = 1 \). This concept is crucial in many mathematical fields.
In the realm of modular arithmetic, especially in a finite field such as \( \mathbb{Z}_p \), the idea is similar, but with a little twist. Here, numbers wrap around upon reaching a certain value, \( p \), known as the modulus. An element \( a \) in \( \mathbb{Z}_p \) has a multiplicative inverse if there exists another element \( b \) such that
In the realm of modular arithmetic, especially in a finite field such as \( \mathbb{Z}_p \), the idea is similar, but with a little twist. Here, numbers wrap around upon reaching a certain value, \( p \), known as the modulus. An element \( a \) in \( \mathbb{Z}_p \) has a multiplicative inverse if there exists another element \( b \) such that
- \( a \times b \equiv 1 \mod p \).
Modular Arithmetic
At its core, modular arithmetic is like the arithmetic we are used to, but one where numbers wrap around upon reaching a certain point, the modulus. Imagine the numbers on a clock: when you go past 12, you start again from 1. This circular nature is what modular arithmetic embodies. For a modulus \( p \), this arithmetic deals with remaindersfrom division by \( p \).
For instance, in the exercise, two particular elements, 1 and \( p-1 \), demonstrate how they square back to one under \( p \):
- For example, \(15 \equiv 3 \mod 12\) because when you divide 15 by 12, the remainder is 3.
For instance, in the exercise, two particular elements, 1 and \( p-1 \), demonstrate how they square back to one under \( p \):
- \( 1 \times 1 \equiv 1 \mod p \) and
- \((p-1) \times (p-1) \equiv 1 \mod p \)
Finite Fields
Finite fields, often denoted as \( \mathbb{Z}_p \), hold a special place in mathematics, especially when \( p \) is a prime number. These fields are a set of finite numbers where you can perform operations like addition, subtraction, multiplication, and taking inverses, and always get a result that belongs to the same set. This unique set structure is what makes a finite field useful in many applications, such as cryptography and coding theory.
One of the intriguing aspects of finite fields is how they simplify problem-solving by constraining results within a small set of numbers. In a finite field of prime order, every non-zero element has a multiplicative inverse, meaning that if you multiply an element by its inverse, you'll always get 1. This property is a defining characteristic.
In our example with \( \mathbb{Z}_p \), whenever we consider the equation \( a^2 \equiv 1 \mod p \), we see that only elements 1 and \( p-1 \) satisfy it.
One of the intriguing aspects of finite fields is how they simplify problem-solving by constraining results within a small set of numbers. In a finite field of prime order, every non-zero element has a multiplicative inverse, meaning that if you multiply an element by its inverse, you'll always get 1. This property is a defining characteristic.
In our example with \( \mathbb{Z}_p \), whenever we consider the equation \( a^2 \equiv 1 \mod p \), we see that only elements 1 and \( p-1 \) satisfy it.
- For 1, inversing itself yields \(1 \times 1 \equiv 1 \mod p \).
- For \( p-1 \), its inverse operation returns to 1, as \((p-1) \times (p-1) \equiv 1 \mod p \).