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Mark each of the following true or false. a. Every factor group of a cyclic group is cyclic. b. A factor group of a noncyclic group is again noncyclic. c. \(\mathbb{R} / \mathrm{Z}\) under addition has no element of order 2 . d. \(\mathbb{R} / \mathbf{Z}\) under addition has elements of order \(n\) for all \(n \in \mathbb{Z}\). . e. \(\mathbb{R} / Z\) under addition has an infinite number of elements of order \(4 .\) f. If the commutator subgroup \(C\) of a group \(G\) is \(\mid e\\}\), then \(G\) is abelian. g. If \(G / H\) is abelian, then the commutator subgroup of \(C\) of \(G\) contains \(H\). h. The commutator subgroup of a simple group \(G\) must be \(G\) itself. i. The commutator subgroup of a nonabelian simple group \(G\) must be \(G\) itself. j. All nontrivial finite simple groups have prime order.

Short Answer

Expert verified
a. True, b. False, c. False, d. True, e. True, f. True, g. False, h. True, i. True, j. False.

Step by step solution

01

Evaluate Statement a

Statement: Every factor group of a cyclic group is cyclic. Theorem: A factor group of a cyclic group is always cyclic because the quotient of a cyclic group by any of its subgroups is also cyclic. Therefore, the statement is **True**.
02

Evaluate Statement b

Statement: A factor group of a noncyclic group is again noncyclic.Counterexample: Consider the symmetric group on 3 elements, \( S_3 \), which is noncyclic. Its factor group \( S_3/ A_3 \) is cyclic, specifically \( \mathbb{Z}_2 \).Therefore, the statement is **False**.
03

Evaluate Statement c

Statement: \( \mathbb{R}/\mathbb{Z} \) under addition has no element of order 2.Consider the element \(1/2 + \mathbb{Z} \), which when added to itself gives \(1 + \mathbb{Z} = 0 + \mathbb{Z} \), fulfilling the condition for having order 2.Therefore, the statement is **False**.
04

Evaluate Statement d

Statement: \( \mathbb{R}/\mathbb{Z} \) under addition has elements of order \(n\) for all \(n \in \mathbb{Z}^+\).Elements of the form \(k/n + \mathbb{Z}\) (where \(k\) and \(n\) are integers) have order \(n\), proving the statement is true for all positive integers \(n\).Therefore, the statement is **True**.
05

Evaluate Statement e

Statement: \( \mathbb{R}/\mathbb{Z} \) under addition has an infinite number of elements of order 4.Elements like 1/4, 3/4, 5/4, etc., all have order 4, and there are infinitely many such fractions.Therefore, the statement is **True**.
06

Evaluate Statement f

Statement: If the commutator subgroup \(C\) of a group \(G\) is \( \{e\} \), then \(G\) is abelian.The commutator subgroup being trivial implies all commutators are identity, meaning any two elements in \(G\) commute.Therefore, the statement is **True**.
07

Evaluate Statement g

Statement: If \(G/H\) is abelian, then the commutator subgroup \(C\) of \(G\) contains \(H\).While \(G/H\) being abelian ensures all commutators are in \(H\), it does not necessarily mean \(C\) contains \(H\). It means \(H\) might be trivial instead of contained in \(C\).Therefore, the statement is **False**.
08

Evaluate Statement h

Statement: The commutator subgroup of a simple group \(G\) must be \(G\) itself.If \(G\) were abelian, the commutator subgroup would be \( \{e\} \), but a simple group is not abelian.Therefore, the statement is **True**.
09

Evaluate Statement i

Statement: The commutator subgroup of a nonabelian simple group \(G\) must be \(G\) itself.For nonabelian simple groups, which have no nontrivial normal subgroups, the commutator subgroup can't be a proper subgroup.Therefore, the statement is **True**.
10

Evaluate Statement j

Statement: All nontrivial finite simple groups have prime order.Counterexample: The alternating group \(A_5\) is a simple group with order 60, which is not prime.Therefore, the statement is **False**.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cyclic Groups
Cyclic groups are foundational in the study of abstract algebra. A cyclic group is a group that can be generated by a single element, known as a generator. This means every element of the group can be expressed as a power (or multiple) of this generator. Cyclic groups are always abelian, meaning the group operation is commutative: for any two elements \(a\) and \(b\) in the group, \(ab = ba\).
Because they have such a simple structure, cyclic groups are well understood and serve as building blocks for more complicated structures. An example of a finite cyclic group is the integers modulo \(n\), denoted by \(\mathbb{Z}_n\), under addition. The infinite cyclic group is denoted by \(\mathbb{Z}\), which is the set of all integers under addition.
  • Every subgroup of a cyclic group is cyclic.
  • Cyclic groups can be finite or infinite.
  • Factor groups of cyclic groups are also cyclic.
Factor Groups
Factor groups, also known as quotient groups, are formed from a group \(G\) given a normal subgroup \(N\). The set of cosets of \(N\) in \(G\) forms a group, denoted \(G/N\), with the operation defined by \((aN)(bN) = (ab)N\). Factor groups help in simplifying group structures and have wide applications across mathematics.
Factor groups inherit some properties from their parent groups. For example, if \(G\) is abelian, then the factor group \(G/N\) is also abelian. However, factorization can also simplify complex groups: a notable result is that the factor group of a cyclic group is always cyclic. Furthermore, factor groups are crucial in the study of homomorphisms and the Isomorphism Theorems.
  • Useful in reducing the complexity of group problems.
  • Facilitates the study of more complicated groups through simpler structures.
  • Plays a key role in understanding the structure of normal subgroups.
Commutator Subgroup
The commutator subgroup of a group \(G\), often denoted \(G'\) or \([G, G]\), is the subgroup generated by all the commutators in \(G\). A commutator of two elements \(g\) and \(h\) in a group, denoted \([g, h]\), is defined as \(g^{-1}h^{-1}gh\). This subgroup measures how "non-abelian" the group is because, intuitively, the more commutators there are, the less commutative the group is.
The commutator subgroup is always a normal subgroup of \(G\). It is crucial in exploring extensions and understanding the structure of the group. If the commutator subgroup is trivial (consists only of the identity), the group is abelian because all elements commute.
  • Helps determine whether a group is abelian.
  • Provides insights into the structure of non-abelian groups.
  • Always a normal subgroup.
Simple Groups
Simple groups are those with no nontrivial normal subgroups other than the group itself and the identity. They can be thought of as the building blocks of all groups, much like prime numbers are the building blocks of integers. Simple groups are foundational in the classification of finite groups.
A simple group can be abelian or nonabelian. If it's abelian, it must be isomorphic to \(\mathbb{Z}_p\), a cyclic group of prime order \(p\). Nonabelian simple groups are more complex and include important families such as the alternating group \(A_n\) for \(n > 4\).
  • Essential for understanding the structure of larger groups.
  • Finite simple groups were classified completely in the 20th century.
  • Integral to the classification theorem for finite groups.

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Most popular questions from this chapter

In Exercises 1 through 12, classify the given group according to the fundamental theorem of finitely generated abelian groups. $$ \left(\mathrm{Z}_{2} \times \mathbf{Z}_{4}\right) /\langle(0,1)\rangle $$

Classify the given group acconding to the fundamental theorem of finitely generated abelian groups. $$ \left(Z_{2} \times Z_{4}\right) /((1,2)) $$

Classify the given group acconding to the fundamental theorem of finitely generated abelian groups. $$ (2 \times Z \times Z) /\langle(1,1,1)\rangle $$

Show that if \(G\) is nonabelian, then the factor group \(G / Z(G)\) is not cyclic. [Hint: Show the equivalent contrapositive, namely, that if \(G / Z(G)\) is cyclic then \(G\) is abelian (and hence \(Z(G)=G\) ).]

Prove that \(A_{n}\) is simple for \(n \geq 5\), following the steps and hints given. a. Show \(A_{\text {e contains cuery } 3 \text {-cycle if } n \geq 3 \text {. }}\) b. Show \(A_{n}\) is generated by the 3-cycles for \(n \geq 3\). [Hint: Note that \((a, b)(c, d)=(a, c, b)(a, c, d)\) and \((a, c)(a, b)=(a, b, c) .]\) c. Let \(r\) and \(s\) be fixed elements of \(\\{1,2, \cdots, n]\) for \(n \geq 3\). Show that \(A_{n}\) is generated by the \(n\) "special" 3-cycles of the form \((r, s, i)\) for \(1 \leq i \leq n\) [Hint: Show every 3-cycle is the product of "special" 3-cycles by computing $$ (r, s, i)^{2}, \quad(r, s, f)(r, s, i)^{2}, \quad(r . s, j)^{2}(r, s, i), $$ and $$ (r, s . i)^{2}(r, s, k)(r, s, j)^{2}(r, s, i) $$ Observe that these products give all possible types of 3 -cycles.] d. Let \(N\) be a normal subgroup of \(A_{n}\) for \(n \geq 3\). Show that if \(N\) contains a 3-cycle, then \(N=A_{n}\). [Hint: Show that \((r, s, i) \in N\) implies that \((r, s, j) \in N\) for \(j=1,2, \cdots, n\) by computing $$ \left.((r, s)(i, j))(r, s, i)^{2}((r, s)(i, j))^{-1}\right] $$ e. Let \(N\) be a nontrivial normal subgroup of \(A_{n}\) for \(n \geq 5\). Show that one of the following cases must hold, and conclude in each case that \(N=A_{n}\). Case I \(N\) contains a 3-cycle. Case II \(N\) contains a product of disjoint cycles, at least one of which has length greater than 3. [ Hint: Suppose \(N\) contains the disjoint product \(\sigma=\mu\left(a_{1}, a_{2}, \cdots, a_{n}\right)\). Show \(\sigma^{-1}\left(a_{1}, a_{2}, a_{3}\right) \sigma\left(a_{1}, a_{2}, a_{3}\right)^{-1}\) is in \(N\). and compute it.] Case III \(N\) contains a disjoint product of the form \(\sigma=\mu\left(a_{4}, a_{5}, a_{6}\right)\left(a_{1}, a_{2}, a_{3}\right)\). [Hint: Show \(\sigma^{-1}\left(a_{1}, a_{2}, a_{4}\right)\) \(\sigma\left(a_{1}, a_{2}, a_{4}\right)^{-1}\) is in \(N\), and compute it.\\} Case IV \(N\) contains a disjoint product of the form \(\sigma=\mu\left(a_{1}, a_{2}, a_{3}\right)\) where \(\mu\) is a product of disjoint 2 -cycles. [Hint: Show \(\sigma^{2} \in N\) and compute it.] Case \(\mathbf{V} N\) contains a disjoint product \(\sigma\) of the form \(\sigma=\mu\left(a_{3}, a_{4}\right)\left(a_{1}, a_{2}\right)\), where \(\mu\) is a product of an cven number of disjoint 2-cycles. [Hint: Show that \(\sigma^{-1}\left(a_{1}, a_{2}, a_{3}\right) \sigma\left(a_{1}, a_{2}, a_{3}\right)^{-1}\) is in \(N\), and compute, it to deduce that \(\alpha=\left(a_{2}, a_{4}\right)\left(a_{1}, a_{3}\right)\) is in \(N\). Using \(n \geq 5\) for the first time, find \(i \neq a_{1}, a_{2}, a_{3}, a_{3}\) in \(\\{1,2, \ldots, n]\). Let \(\beta=\left(a_{1}, a_{1}, i\right)\). Show that \(\beta^{-1} \alpha \beta \alpha \in N\), and compute it.]

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