Chapter 5: Problem 3
Show that if an element \(y\) of a group \(G\) is in the right coset \(H x\) then \(H y=H x\)
Short Answer
Expert verified
If \( y \in Hx \), then \( Hy = Hx \) by proving both inclusions.
Step by step solution
01
Define Elements in Coset
We need to recall that a right coset of a subgroup \( H \) in a group \( G \) with an element \( x \) is the set \( Hx = \{ hx : h \in H \} \). To show \( Hy = Hx \), we must show that any element \( y = hx \), \( y \in Hx \), can be expressed through elements in \( H \) such that \( Hy = Hx \).
02
Express the Right Coset Equality
Assume \( y \in Hx \), which means \( y = hx \) for some \( h \in H \). We want to show \( Hy = \{ hy : h \in H \} = \{ h'x : h' \in H \} = Hx \).
03
Show Inclusion of Cosets
First show that \( Hy \subseteq Hx \):- For \( g \in Hy \), there exists some \( h \in H \) so that \( g = hy = h(hx) = (hh')x \) for some \( h' \in H \). Therefore, \( g \in Hx \). This shows that \( Hy \subseteq Hx \).
04
Prove Coset Equality
Next, show \( Hx \subseteq Hy \):- For \( g \in Hx \), there exists some \( h' \in H \) such that \( g = h'x \). Notice we can write \( g = h'(hx) = (h'h)y \) where \( h, h' \in H \). Therefore, \( g \in Hy \). This shows \( Hx \subseteq Hy \). - Since both inclusions are shown, \( Hy = Hx \).
05
Conclude the Equality
Having shown both \( Hy \subseteq Hx \) and \( Hx \subseteq Hy \), by definition of set equality, \( Hy = Hx \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cosets
In group theory, a coset is formed when a subgroup combines with an element of the overall group. This concept is pivotal because it helps to break down a group into simpler, more manageable pieces. Specifically, a right coset of a subgroup \( H \) with respect to an element \( x \) in a group \( G \) is represented as \( Hx \). This notation implies the set of all products of the form \( hx \) where \( h \) belongs to \( H \).
For example, if we consider a group \( G \) and a subgroup \( H \) within it, selecting an element \( x \) from \( G \) will form the coset \( Hx \). All elements \( y \) that can be expressed as a product \( y = hx \) for any \( h \) in \( H \) belong to this right coset. The importance of cosets lies in their ability to partition a group into disjoint subsets that evenly distribute the elements of the entire group.
For example, if we consider a group \( G \) and a subgroup \( H \) within it, selecting an element \( x \) from \( G \) will form the coset \( Hx \). All elements \( y \) that can be expressed as a product \( y = hx \) for any \( h \) in \( H \) belong to this right coset. The importance of cosets lies in their ability to partition a group into disjoint subsets that evenly distribute the elements of the entire group.
Subgroup
A subgroup is essentially a subset of a group that itself forms a group under the same operation used on the parent group. To qualify as a subgroup, this set must satisfy several properties.
- Closure: For any two elements \( a \) and \( b \) in the subgroup \( H \), their product \( ab \) must also be in \( H \).
- Identity: The subgroup must include the identity element of the group \( G \).
- Inverses: For every element \( a \) in \( H \), there must be an inverse element in \( H \) such that \( aa^{-1} = e \), where \( e \) is the identity element.
Group Elements
Group elements are the individual entities that make up a group in group theory. Each element in a group interacts with every other element through a specific operation defined for the group, such as addition or multiplication.
Let's break it down further with simple points:
Let's break it down further with simple points:
- Operation: The defined operation (for example, multiplication or addition) determines how the elements interact with each other within the group.
- Identity Element: This special element, denoted as \( e \), when combined with any element \( a \) of the group under the group operation, will return \( a \) (i.e., \( ae = a \)).
- Inverse Element: For each element \( a \) in the group, there exists an element \( b \) such that when they are combined using the group operation, they yield the identity element (i.e., \( ab = e \)).