Let \(f, g, h:[a, b] \rightarrow \mathbb{R}\) be continuous on \([a, b]\) and
differentiable on \((a, b)\). Show that there is \(c \in(a, b)\) such that the \(3
\times 3\) determinant
$$
\left|\begin{array}{ccc}
f(a) & f(b) & f^{\prime}(c) \\
g(a) & g(b) & g^{\prime}(c) \\
h(a) & h(b) & h^{\prime}(c)
\end{array}\right|
$$
is zero, that is, \(f(a)\left(g(b) h^{\prime}(c)-h(b)
g^{\prime}(c)\right)-f(b)\left(g(a) h^{\prime}(c)-h(a) g^{\prime}(c)\right)+\)
\(f^{\prime}(c)(g(a) h(b)-h(a) g(b))=0\). Deduce that if \(h(x)=1\) for all \(x
\in[a, b]\), we obtain the conclusion of the Cauchy Mean Value Theorem
(Proposition 4.38). What does the result say if \(g(x)=x\) and \(h(x)=1\) for all
\(x \in[a, b] ?\)