Chapter 2: Problem 30
Let \(n\) be an integer greater than \(1 .\) Show that \(n\) does not divide \(2^{n}-1\).
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Chapter 2: Problem 30
Let \(n\) be an integer greater than \(1 .\) Show that \(n\) does not divide \(2^{n}-1\).
These are the key concepts you need to understand to accurately answer the question.
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et \(n\) be a positive integer, and write \(n=a b^{2}\) where \(a\) and \(b\) are positive integers, and \(a\) is square-free (see Exercise 1.15). Show that \(n\) is the sum of two squares of integers if and only if no prime \(p \equiv 3(\bmod 4)\) divides \(a\). Hint: use the previous two exercises.
Define \(\sigma(n):=\sum_{d \mid n} d\). Show that: (a) \(\sigma\) is a multiplicative function; (b) \(\sigma(n)=\prod_{i=1}^{r}\left(p_{i}^{e_{i}+1}-1\right) /\left(p_{i}-1\right),\) where \(n=p_{1}^{e_{1}} \cdots p_{r}^{e_{r}}\) is the prime factorization of \(n\) (c) \(\sum_{d \mid n} \mu(d) \sigma(n / d)=n\) (d) \(\sum_{d \mid n} \mu(d) \sigma(d)=(-1)^{r} p_{1} \cdots p_{r},\) where \(n=p_{1}^{e_{1}} \cdots p_{r}^{e_{r}}\) is the prime factorization of \(n\).
Let \(a, b, n \in \mathbb{Z}\) with \(n>0\). Show that \(a \equiv b(\bmod n)\) if and only if \((a \bmod n)=(b \bmod n)\).
Let \(n \in \mathbb{Z}\) with \(n>1 .\) Show that \(n\) is prime if and only if \(\alpha^{n-1}=1\) for every non-zero \(\alpha \in \mathbb{Z}_{n}\).
Show that if \(n\) is divisible by \(r\) distinct odd primes, then \(2^{r} \mid \varphi(n)\).
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