Chapter 10: Problem 8
Let \(G\) and \(H\) be topological groups and \(\phi: U \rightarrow H\) a map on a connected open neighborhood \(U\) of \(e \in G\) such that \(\phi(a b)=\phi(a) \phi(b)\) when \(a, b, a b \in U\) (a) For each \(c \in G\), consider pairs \((V, \psi)\), where \(V \subset G\) is an open neighborhood of \(c\) with \(V \cdot V^{-1} \subset U\), and where \(\psi: V \rightarrow H\) satisfies \(\psi(a) \cdot \psi(b)^{-1}=\) \(\phi\left(a b^{-1}\right)\) for \(a, b \in V\). Define \(\left(V_{1}, \psi_{1}\right) \sim\left(V_{2}, \psi_{2}\right)\) if \(\psi_{1}=\psi_{2}\) on some smaller neighborhood of \(c\). Show that the set of all \(\widetilde{c}\) equivalence classes, for all \(c \in G\), can be made into a covering space of \(G\). (b) Conclude that if \(G\) is simply-connected, then \(\phi\) can be extended uniquet: to a homomorphism of \(G\) into \(H\).
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.