Chapter 4: Problem 8
Let \(S\) denotes the set of all values of \(x\) for which the equation \(2 x^{2}-2(2 a+1) x+a(a+1)=0\) has one root less than \(a\) and other root greater than \(a\), then \(S\) equals (A) \((0,1)\) (B) \((-1,0)\) (C) \((0,1 / 2)\) (D) None of these
Short Answer
Expert verified
The set \( S \) equals (C) \((0, 1/2)\).
Step by step solution
01
Understand the Nature of Roots
For a quadratic equation of the form \( ax^2+bx+c=0 \), if we need one root \( r_1 < a \) and another root \( r_2 > a \), then the quadratic equation should have real roots such that they lie around the value \( a \).
02
Establish the Condition for Real Roots
For the quadratic \( 2x^2 - 2(2a+1)x + a(a+1) = 0 \) to have real roots, the discriminant \( \Delta \) must be non-negative. Compute the discriminant: \[ \Delta = [2(2a+1)]^2 - 4 \times 2 \times a(a+1). \] Simplifying, \[ \Delta = 8a^2 + 8a + 4 - 8a^2 - 8a = 4. \] Thus, \( \Delta = 4 \), which is positive, ensuring real roots.
03
Apply Vieta's Formulas
By Vieta's formulas, the sum of the roots \( r_1 + r_2 = \frac{2(2a+1)}{2} = 2a+1 \) and the product of the roots \( r_1r_2 = \frac{a(a+1)}{2} \). For one root to be less than \( a \) and the other to be greater than \( a \), the sum \( r_1 + r_2 = 2a+1 \) must satisfy this condition geometrically.
04
Derive the Set S
The condition \( r_1 < a < r_2 \) implies the vertex of the parabola \( x = \frac{-b}{2a} \), which equals \( 1 \). Thus, \( a \) is centered between the roots in such a way that one root is less than \( a \) and the other greater. Analyzing the structure, this holds true when \( 0 < a < \frac{1}{2} \).
05
Compare with Choices
The interval derived from the condition \( 0 < a < \frac{1}{2} \) matches Option C, which is \((0, 1/2)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Nature of Roots
Quadratic equations of the form \( ax^2 + bx + c = 0 \) often have two solutions known as roots. The nature of these roots can tell us how they behave in relation to a specific value \( a \).
Consider a scenario where one root needs to be less than a value \( a \) and the other root greater than \( a \). This is a specific situation where the roots "straddle" the value \( a \). In geometrical terms, this means the parabola opens around \( a \), such that the roots \( r_1 \) and \( r_2 \) are placed opposite sides of \( a \).
For real roots that satisfy this condition to exist, they must meet certain criteria:
Consider a scenario where one root needs to be less than a value \( a \) and the other root greater than \( a \). This is a specific situation where the roots "straddle" the value \( a \). In geometrical terms, this means the parabola opens around \( a \), such that the roots \( r_1 \) and \( r_2 \) are placed opposite sides of \( a \).
For real roots that satisfy this condition to exist, they must meet certain criteria:
- The quadratic equation must have real roots. This ensures the equation indeed has valid solutions.
- The value \( a \) must be centered between the roots, causing one to be less and the other more than \( a \).
Discriminant of a Quadratic Equation
The discriminant of a quadratic equation plays a critical role in determining the nature of its roots. For a quadratic equation \( ax^2 + bx + c = 0 \), the discriminant \( \Delta \) is calculated as \( b^2 - 4ac \).
The value of the discriminant tells us the following:
This positive discriminant ensures the roots will behave in a predictable manner, allowing further analysis using geometrical or algebraic methods as needed.
The value of the discriminant tells us the following:
- If \( \Delta > 0 \), the equation has two distinct real roots.
- If \( \Delta = 0 \), it has exactly one real root, also known as a repeated or double root.
- If \( \Delta < 0 \), the roots are complex or imaginary, meaning real roots do not exist.
This positive discriminant ensures the roots will behave in a predictable manner, allowing further analysis using geometrical or algebraic methods as needed.
Vieta's Formulas
Vieta's formulas provide a direct relationship between the coefficients of a polynomial and sums and products of its roots.
For a quadratic equation \( ax^2 + bx + c = 0 \), Vieta's formulas state:
Understanding and applying Vieta's formulas helps solve problems more intuitively and efficiently, making them a powerful tool in quadratic equations.
For a quadratic equation \( ax^2 + bx + c = 0 \), Vieta's formulas state:
- The sum of the roots \( r_1 + r_2 = -\frac{b}{a} \).
- The product of the roots \( r_1r_2 = \frac{c}{a} \).
- Sum of roots: \( r_1 + r_2 = 2a + 1 \).
- Product of roots: \( r_1r_2 = \frac{a(a+1)}{2} \).
Understanding and applying Vieta's formulas helps solve problems more intuitively and efficiently, making them a powerful tool in quadratic equations.