Chapter 4: Problem 67
If \(p x^{2}+q x+r=0\) has no real roots and \(p, q, r\) are real such that \(p+r>0\), then (A) \(p-q+r \leq 0\) (B) \(p+r \geq q\) (C) \(p+r=q\) (D) None of these
Short Answer
Expert verified
The correct option is (B).
Step by step solution
01
Understand Discriminant of a Quadratic Equation
A quadratic equation of the form \( ax^2 + bx + c = 0 \) has no real roots if its discriminant \( b^2 - 4ac \) is less than zero.
02
Apply Discriminant Condition
For the given quadratic equation \( p x^2 + q x + r = 0 \), the discriminant is \( q^2 - 4pr \). Since the equation has no real roots, we have \( q^2 - 4pr < 0 \).
03
Investigate Given Condition
We are given that \( p + r > 0 \). This condition will be used in conjunction with other options to find a relation among \( p, q, \) and \( r \).
04
Analyze Each Option
- For option (A), if \( p - q + r \leq 0 \), this implies \( p + r \leq q \). However, this does not necessarily lead to \( q^2 < 4pr \) because the opposite is considered.- For option (B), if \( p + r \geq q \), it implies \( p + r > q \) when combined with \( q^2 - 4pr < 0 \), making sense since it could lead to \( q^2 < (p+r)^2 \).- For option (C), if \( p + r = q \), \( q^2 - 4pr < 0 \) doesn't always hold.- Option (D) would imply none of these conditions satisfy all given conditions.
05
Conclude the Correct Option
By deducing from the inequalities, option (B): \( p+r \geq q \) leads naturally to fulfilling the conditions set by having no real roots and \( p + r > 0 \). Therefore, the correct answer is option (B).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Discriminant of Quadratic Equation
The discriminant is a critical part of every quadratic equation, helping us determine the nature of its roots. Given a quadratic equation in the standard form \( ax^2 + bx + c = 0 \), the discriminant is expressed as \( b^2 - 4ac \). This part of the quadratic formula helps to indicate the type of roots the equation has.
- If the discriminant \( b^2 - 4ac > 0 \), the equation has two distinct real roots.
- If \( b^2 - 4ac = 0 \), it has exactly one real root or a repeated root.
- If \( b^2 - 4ac < 0 \), there are no real roots; instead, the roots are complex conjugates.
Inequalities with Quadratics
Quadratic inequalities involve expressions where a quadratic function is set in relation to another value, like solving for \( ax^2 + bx + c > 0 \). These inequalities require understanding how quadratics behave over intervals.
For our exercise, given \( q^2 - 4pr < 0 \), we know it aligns with quadratics having complex roots. This inequality tells us about the relationship and sums of \( p \), \( q \), and \( r \) in our quadratic. It means not only are there no real roots, but graphically, the parabola doesn't cross the x-axis at all. Combined with \( p + r > 0 \), these inequalities suggest viable solutions must meet simultaneous conditions.
For our exercise, given \( q^2 - 4pr < 0 \), we know it aligns with quadratics having complex roots. This inequality tells us about the relationship and sums of \( p \), \( q \), and \( r \) in our quadratic. It means not only are there no real roots, but graphically, the parabola doesn't cross the x-axis at all. Combined with \( p + r > 0 \), these inequalities suggest viable solutions must meet simultaneous conditions.
- Checking each proposed condition in the exercise, we found that \( p + r \geq q \) fits well with no real roots, as it supports the condition \( q^2 < 4pr \).
Real and Complex Roots
The nature of the roots of a quadratic equation is crucial to understanding its solutions and graph. Real roots are where the quadratic can intersect the x-axis, while complex roots indicate no intersection.
For quadratic equations such as \( p x^2 + q x + r = 0 \), if \( q^2 - 4pr < 0 \), the roots are complex. Let's break down complex roots:
For quadratic equations such as \( p x^2 + q x + r = 0 \), if \( q^2 - 4pr < 0 \), the roots are complex. Let's break down complex roots:
- Complex numbers are in the form \( a + bi \), where \( i \) is the imaginary unit satisfying \( i^2 = -1 \).
- Complex roots always occur in conjugate pairs, such as \( a + bi \) and \( a - bi \), ensuring the roots are symmetric about the real axis.