Chapter 3: Problem 207
If \(\left|Z-\frac{4}{Z}\right|=2\), then the maximum value of \(|Z|\) is equal to (A) \(\sqrt{3}+1\) (B) \(\sqrt{5}+1\) (C) 2 (D) \(2+\sqrt{2}\)
Short Answer
Expert verified
The maximum value of \(|Z|\) is 2, corresponding to option (C).
Step by step solution
01
Understand the Given Equation
We are given that \( |Z - \frac{4}{Z}| = 2 \), where \(Z\) is a complex number. The expression represents the distance between the complex number \(Z\) and \(\frac{4}{Z}\) on the complex plane being equal to 2.
02
Rewrite the Equation in Terms of Real and Imaginary Parts
Let \( Z = x + yi \), where \( x \) and \( y \) are real numbers and \( i \) is the imaginary unit. Then \( \frac{4}{Z} = \frac{4}{x + yi} \). Express \( \frac{4}{Z} \) in real and imaginary terms by multiplying the numerator and denominator by the conjugate: \( \frac{4(x-yi)}{x^2 + y^2} \). Thus:\[ Z - \frac{4}{Z} = (x + yi) - \left( \frac{4x}{x^2+y^2} \right) - \left( \frac{4y}{x^2+y^2} \right)i \].
03
Solve for Modulus
The modulus \( |Z - \frac{4}{Z}| = 2 \) can now be expressed using real components: \\[ \left( x - \frac{4x}{x^2+y^2} \right)^2 + \left( y - \frac{4y}{x^2+y^2} \right)^2 = 4 \].
04
Analyze for Maximum |Z| by Substitution
Try substitutions or geometrical interpretations to simplify calculations. Assume \( |Z| = r \), where \( r = \sqrt{x^2+y^2} \), and substitute to check consistency: \[ |Z|^2 + \left| \frac{4}{Z} \right|^2 - 2\frac{4}{|Z|} = 4 \] implies \[ r^2 + \frac{16}{r^2} - 8 = 4 \]. Solve for \( r \).
05
Solve Quadratice Equation
Simplify the equation derived in Step 4: \[ r^4 - 8r^2 + 16 = 0 \].\Use substitution \( u = r^2 \) leading to \( u^2 - 8u + 16 = 0 \). Solve for \( u \). By factorizing, \( (u-4)^2 = 0 \) giving \( u = 4 \). Then \( r = \sqrt{4} = 2 \).
06
Calculate |Z| and Cross Check Options
The value obtained for \(|Z|\) is 2. Cross-check against given options (A-D). The maximum value 2 matches option (C).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Modulus of a Complex Number
The modulus of a complex number is a fundamental concept. It measures how far a point, representing the complex number, is from the origin in the complex plane. For a complex number expressed as \( Z = x + yi \), where \( x \) is the real part and \( y \) is the imaginary part, the modulus of \( Z \) is calculated using the formula:
- \( |Z| = \sqrt{x^2 + y^2} \)
Distance in the Complex Plane
Understanding distance in the complex plane aids in visualizing and solving problems involving complex numbers. The complex plane is similar to a Cartesian coordinate system, with the real and imaginary parts of a complex number acting like the x and y coordinates. The distance between two complex numbers \( Z_1 = x_1 + y_1i \) and \( Z_2 = x_2 + y_2i \) is calculated using:
- \( |Z_1 - Z_2| = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \)
Solving Quadratic Equations
Quadratic equations often appear in problems involving complex numbers due to their squared terms. In the exercise, after substituting and simplifying, we encountered a quadratic equation of the form \( u^2 - 8u + 16 = 0 \). Here, \( u \) represents \( r^2 \), which comes from expressing the modulus \(|Z|\) in terms of real numbers.To solve quadratic equations:
- Utilize the general formula for roots: \( u = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
- In this case, the equation \((u - 4)^2 = 0\) was solved by recognizing its perfect square form, directly providing \( u = 4 \).