Chapter 3: Problem 146
If \(\alpha, \beta\) are the roots of \(z+\frac{1}{z}=2(\cos \theta+\sin \theta)\) Then, (A) \(|\alpha-i|>|\beta-i|\) (B) \(|\alpha-i|<|\beta-i|\) (C) \(|\alpha-i|=|i-\beta|\) (D) \(|\alpha-i|=|\beta-i|\)
Short Answer
Expert verified
Option (D): \(|\alpha-i|=|\beta-i|\).
Step by step solution
01
Understanding the Equation
The equation given is \( z + \frac{1}{z}=2(\cos \theta + \sin \theta) \). This can be interpreted in the complex plane where \( z = r e^{i\theta} \) is a complex number with roots \( \alpha \) and \( \beta \), and \( |z| = 1 \) since \( z \cdot \frac{1}{z} = 1 \).
02
Rewrite the Equation for Roots
Rewrite the equation as a quadratic: \( z^2 - 2(\cos \theta + \sin \theta)z + 1 = 0 \).
03
Determine Roots using Vieta's Formulas
Vieta's formulas tell us the roots \( \alpha \) and \( \beta \) are given by: \( \alpha + \beta = 2(\cos \theta + \sin \theta) \) and \( \alpha\beta = 1 \).
04
Substitute and Solve for Roots
Given \( \alpha + \beta = 2(\cos \theta + \sin \theta) \), write roots as \( \alpha = e^{i(\theta + \phi)} \) and \( \beta = e^{i(\theta - \phi)} \), based on their angular symmetry.
05
Calculate Distances and Compare
Because the magnitude of both roots \( |\alpha| = |\beta| = 1 \) and they lie symmetrically about the angle \( \theta \), the distances \( |\alpha - i| \) and \( |\beta - i| \) are equal. Thus, \[ |\alpha - i| = |\beta - i|. \]
06
Conclusion
Therefore, the correct answer is that the distances from the imaginary axis are equal for both roots. Thus, \(|\alpha - i| = |\beta - i|\), which corresponds to option (D).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vieta's Formulas
Vieta's Formulas are a fantastic way to link the coefficients of a polynomial to the sum and product of its roots. They're especially handy when solving quadratic equations. For any quadratic equation of the form:
- \( ax^2 + bx + c = 0 \)
- The sum of the roots, \( \alpha + \beta = -\frac{b}{a} \)
- The product of the roots, \( \alpha\beta = \frac{c}{a} \)
- \( z^2 - 2(\cos \theta + \sin \theta)z + 1 = 0 \)
- The sum of the roots \( \alpha + \beta = 2(\cos \theta + \sin \theta) \)
- The product of the roots \( \alpha\beta = 1 \)
Quadratic Equations
Quadratic equations are at the heart of algebra. They usually appear in the form:
- \( ax^2 + bx + c = 0 \)
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
- \( z^2 - 2(\cos \theta + \sin \theta)z + 1 = 0 \)
Complex Plane
The complex plane is a two-dimensional plane where we can visualize complex numbers. Each complex number is represented as a point or a vector in this plane, defined by:
- \( z = x + yi \)
- \( |z| = r \) is the magnitude
- \( \theta \) is the angle formed with the positive real axis