Chapter 21: Problem 87
For any vector \(\vec{a}\), the value of \((\vec{a} \times \hat{i})^{2}+(\vec{a} \times \hat{j})^{2}+(\vec{a} \times \hat{k})^{2}\) is equal to (A) \(3 \vec{a}^{2}\) (B) \(\vec{a}^{2}\) (C) \(2 \vec{a}^{2}\) (D) \(4 \vec{a}^{2}\)
Short Answer
Expert verified
The expression simplifies to \(2 \vec{a}^{2}\), hence the correct option is (C).
Step by step solution
01
Understanding the Problem
We need to evaluate the expression \((\vec{a} \times \hat{i})^2 + (\vec{a} \times \hat{j})^2 + (\vec{a} \times \hat{k})^2\), where \(\vec{a}\) is any vector, and \(\hat{i}, \hat{j}, \hat{k}\) are unit vectors along the x, y, and z axes. The task is to express this in terms of \(\vec{a}^2\) and choose the correct option from the given choices.
02
Vector Representation
Let the vector \(\vec{a} = a_x \hat{i} + a_y \hat{j} + a_z \hat{k}\), where \(a_x, a_y, a_z\) are the components of \(\vec{a}\) along the x, y, and z axes respectively.
03
Calculate \(\vec{a} \times \hat{i}\)
The cross product \(\vec{a} \times \hat{i} = (0 \cdot (a_z \cdot \hat{k}) - a_y \cdot (1 \cdot \hat{k}), a_x \cdot (0) - a_z \cdot (1), a_y \cdot (1) - a_x \cdot (0)) \). This simplifies to \([-a_y \hat{k} + a_z \hat{j}]\).
04
Calculate \((\vec{a} \times \hat{i})^2\)
The square of a vector \([-a_y \hat{k} + a_z \hat{j}]\) is its dot product with itself. So, \((\vec{a} \times \hat{i})^2 = (-a_y)^2 + (a_z)^2 = a_y^2 + a_z^2\).
05
Calculate \(\vec{a} \times \hat{j}\)
The cross product \(\vec{a} \times \hat{j} = a_z \hat{i} - a_x \hat{k}\).
06
Calculate \((\vec{a} \times \hat{j})^2\)
The square of a vector \(a_z \hat{i} - a_x \hat{k}\) is \((a_z)^2 + (-a_x)^2 = a_z^2 + a_x^2\).
07
Calculate \(\vec{a} \times \hat{k}\)
The cross product \(\vec{a} \times \hat{k} = a_x \hat{j} - a_y \hat{i}\).
08
Calculate \((\vec{a} \times \hat{k})^2\)
The square of the vector \(a_x \hat{j} - a_y \hat{i}\) is \((a_x)^2 + (-a_y)^2 = a_x^2 + a_y^2\).
09
Sum the Results
Add the results from Steps 4, 6, and 8: \((a_y^2 + a_z^2) + (a_z^2 + a_x^2) + (a_x^2 + a_y^2) = 2(a_x^2 + a_y^2 + a_z^2) = 2 \vec{a}^2\).
10
Conclusion
The expression \((\vec{a} \times \hat{i})^2 + (\vec{a} \times \hat{j})^2 + (\vec{a} \times \hat{k})^2\) simplifies to \(2 \vec{a}^2\). Therefore, the correct choice is (C) \(2 \vec{a}^2\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
The cross product, often denoted by \( \vec{a} \times \vec{b} \), represents a vector that is perpendicular to both vectors \( \vec{a} \) and \( \vec{b} \). To determine the cross product, we can use the determinant of a 3x3 matrix involving the unit vectors \( \hat{i}, \hat{j}, \hat{k} \):
- The top row holds these unit vectors.
- The second row contains the components of vector \( \vec{a} \).
- The third row has the components of vector \( \vec{b} \).
- \( (a_yb_z - a_zb_y) \hat{i} \)
- \( -(a_xb_z - a_zb_x) \hat{j} \)
- \( (a_xb_y - a_yb_x) \hat{k} \)
Vector Magnitude
The magnitude of a vector, sometimes referred to as the length or norm of the vector, is a measure of how long the vector is. For a vector \( \vec{a} = a_x \hat{i} + a_y \hat{j} + a_z \hat{k} \), its magnitude \( |\vec{a}| \) is found using the formula:\[|\vec{a}| = \sqrt{a_x^2 + a_y^2 + a_z^2}\]The magnitude of a vector allows us to equate it in scale without regard to direction. It is always a non-negative scalar. In many applications, knowing the vector magnitude is essential, such as when normalizing a vector to determine its unit form.
Unit Vectors
Unit vectors are vectors with a magnitude of one. They are used to specify direction. In three-dimensional space, the most commonly used unit vectors are \( \hat{i}, \hat{j}, \hat{k} \), representing the x, y, and z axes, respectively.
- \( \hat{i} = (1, 0, 0) \)
- \( \hat{j} = (0, 1, 0) \)
- \( \hat{k} = (0, 0, 1) \)
Vector Components
Vector components are the projections of a vector along the axes of a coordinate system. They define the vector in terms of its directional influences along each axis. For a vector \( \vec{a} = a_x \hat{i} + a_y \hat{j} + a_z \hat{k} \), \( a_x, a_y, \) and \( a_z \) are its components.
- These components clarify how the vector moves along the x, y, and z directions.
- Understanding components simplifies vector addition, subtraction, and scalar multiplication.