Chapter 21: Problem 83
Let \(\bar{u}, \bar{v}, \bar{w}\) be such that \(|\bar{u}|=1,|\bar{v}|=2,|\bar{w}|=3\). If the projection \(\bar{v}\) along \(\bar{u}\) is equal to that of \(\bar{w}\) along \(\bar{u}\) and \(\bar{v}, \bar{w}\) are perpendicular to each other then \(\bar{u}-\bar{v}+\bar{w} \mid\) equals (A) 2 (B) \(\sqrt{7}\) (C) \(\sqrt{14}\) (D) 14
Short Answer
Step by step solution
Understanding Projection
Setting up Equal Projections
Calculating Magnitudes
Finding \(\bar{u} - \bar{v} + \bar{w}\)
Substitute Known Values
Simplify the Expression
Determine the Correct Choice
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Magnitudes
Here in the exercise, we have three vectors: \(\bar{u}\), \(\bar{v}\), and \(\bar{w}\), with their magnitudes given as \(1\), \(2\), and \(3\) respectively. These magnitudes help us understand the relative sizes of these vectors.
- \(|\bar{u}| = 1\): This indicates that \(\bar{u}\) is a unit vector, which is the simplest form having a magnitude of one.
- \(|\bar{v}| = 2\): This means \(\bar{v}\) is twice as long as \(\bar{u}\).
- \(|\bar{w}| = 3\): Similarly, \(\bar{w}\) is three times longer than the unit vector \(\bar{u}\).
Understanding these magnitudes is crucial, as they are directly involved in calculations such as projections and finding the resultant magnitude of vector combinations.
Perpendicular Vectors
When vectors are perpendicular, \(\bar{v} \cdot \bar{w} = 0\). This property indicates that they form a 90-degree angle with each other. In our exercise, it's given that \(\bar{v}\) and \(\bar{w}\) are perpendicular.
This leads to:
- Calculation simplification: Knowing this simplifies many calculations, as any component involving the dot product \(\bar{v} \cdot \bar{w}\) can be ignored, assuming a value of zero.
- Geometric visualization: It helps to visualize how these vectors might look geometrically, i.e., forming a right angle in space.
Vector Addition
In our exercise, we consider the expression \(\bar{u} - \bar{v} + \bar{w}\). Understanding vector addition helps us:
- Determine resulting vectors: Use vector addition rules to find the new vector formed by adding or subtracting initial vectors.
- Magnitude calculation: The magnitude of this new vector is found by applying the Euclidean norm to its components – using the formula \(|\bar{c}| = \sqrt{c_1^2 + c_2^2}\).
- Simplification: Each operation affects the vector components, so it's essential for simplification and ensuring accurate results.