Chapter 21: Problem 15
If the vectors \(a\) and \(b\) are perpendicular to each other, then a vector \(v\) in terms of \(a\) and \(b\) satisfying the equations \(v \cdot a=0, v \cdot b=1\) and \([v a b]=1\) is (A) \(\frac{1}{|b|^{2}} b+\frac{1}{|a \times b|^{2}} a \times b\) (B) \(\frac{b}{|b|}+\frac{a \times b}{|a \times b|^{2}}\) (C) \(\frac{b}{|b|^{2}}+\frac{a \times b}{|a \times b|}\) (D) none of these
Short Answer
Step by step solution
Understand Given Conditions
Analyzing Condition v · a = 0
Analyzing Condition v · b = 1
Analyzing Condition [vab] = 1
Construct the Vector v
Match with Options
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Dot Product
\[ \mathbf{a} \cdot \mathbf{b} = a_1b_1 + a_2b_2 + a_3b_3 \]
Here, the result is a single number, which geometrically represents the product of the magnitudes of the two vectors and the cosine of the angle between them.
- When the dot product is zero, it indicates that the vectors are perpendicular (orthogonal).
- If the dot product is positive, the angle is less than 90 degrees.
- If it's negative, the angle is greater than 90 degrees.
Understanding the Scalar Triple Product
\[ \mathbf{a} \cdot ( \mathbf{b} \times \mathbf{c} ) \]
The value can be positive or negative depending on the orientation of the vectors, but the magnitude remains the same. This property is useful in determining if vectors are coplanar:
- When the scalar triple product is zero, the vectors are coplanar—lying on the same plane.
- When it's non-zero, it indicates a volume in 3D space.
Understanding the Cross Product
\[ \mathbf{a} \times \mathbf{b} = (a_2b_3 - a_3b_2, a_3b_1 - a_1b_3, a_1b_2 - a_2b_1) \]
This vector has a direction determined by the right-hand rule, and its magnitude is equal to the area of the parallelogram formed by \( \mathbf{a} \) and \( \mathbf{b} \).
- The cross product is zero when the vectors are parallel (or one is a scalar multiple of the other).
- It has maximum magnitude when the vectors are perpendicular.