Chapter 18: Problem 80
The locus of the vertices of the family of parabolas \(y=\frac{a^{3} x^{2}}{3}+\frac{a^{2} x}{2}-2 a\) is (A) \(x y=\frac{105}{64}\) (B) \(x y=\frac{3}{4}\) (C) \(x y=\frac{35}{16}\) (D) \(x y=\frac{64}{105}\)
Short Answer
Expert verified
(A) \( xy = \frac{105}{64} \).
Step by step solution
01
Identify the General Form of the Parabola
The given equation of the parabola is \( y = \frac{a^3 x^2}{3} + \frac{a^2 x}{2} - 2a \). This is in a form related to \( y = ax^2 + bx + c \), where here the coefficients depend on the parameter \( a \).
02
Determine Vertex of the Parabola
For a parabola in the form \( y = Ax^2 + Bx + C \), the x-coordinate of the vertex is \( x = -\frac{B}{2A} \). Here, \( A = \frac{a^3}{3} \) and \( B = \frac{a^2}{2} \).
03
Calculate x-coordinate of the Vertex
Using the vertex formula, substitute \( A \) and \( B \):\[ x = -\frac{\frac{a^2}{2}}{2 \times \frac{a^3}{3}} = -\frac{\frac{a^2}{2}}{\frac{2a^3}{3}} = -\frac{a^2}{2} \times \frac{3}{2a^3} = -\frac{3}{4a}. \]
04
Calculate y-coordinate of the Vertex
Substitute \( x = -\frac{3}{4a} \) back into the parabola equation:\[ y = \frac{a^3 \left(-\frac{3}{4a}\right)^2}{3} + \frac{a^2 \left(-\frac{3}{4a}\right)}{2} - 2a. \]Calculate each term:\[ \frac{a^3 \left(-\frac{3}{4a}\right)^2}{3} = \frac{a^3 \times \frac{9}{16a^2}}{3} = \frac{9a}{48} = \frac{3a}{16} \]\[ \frac{a^2 \left(-\frac{3}{4a}\right)}{2} = -\frac{3a}{8} \]Combining:\[ y = \frac{3a}{16} - \frac{3a}{8} - 2a = \frac{3a}{16} - \frac{6a}{16} - \frac{32a}{16} = -\frac{35a}{16}. \]
05
Express Relationship Between x and y Coordinates
The locus of the vertices is given by the relationship between \( x \) and \( y \). We found the x-coordinate is \( x = -\frac{3}{4a} \) and the y-coordinate is \( y = -\frac{35a}{16} \). Calculate the product:\[ xy = \left(-\frac{3}{4a}\right) \left(-\frac{35a}{16}\right) = \frac{3 \times 35a}{4a \times 16} = \frac{105}{64}. \]
06
Select the Correct Answer from Options
The product \( xy = \frac{105}{64} \) matches option (A). Hence, the answer is (A).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parabola Equation
The equation of a parabola is a mathematical expression that describes its shape in a coordinate plane. The standard form of a parabola is expressed as \( y = ax^2 + bx + c \). In this equation:
- \( a \) determines the direction and width of the parabola. If \( a \) is positive, the parabola opens upwards, and if negative, it opens downwards.
- \( b \) affects the position of the vertex along the x-axis.
- \( c \) is the y-intercept, showing where the parabola crosses the y-axis.
Vertex Formula
The vertex formula is crucial for locating the highest or lowest point of a parabola, also known as its vertex. The x-coordinate of the vertex is calculated using the formula \( x = -\frac{B}{2A} \), derived from the general parabolic equation \( y = Ax^2 + Bx + C \).In our scenario:
- \( A = \frac{a^3}{3} \)
- \( B = \frac{a^2}{2} \)
Locus Calculation
Locus calculation involves finding a set of points that satisfy a particular condition, forming a shape or path in coordinate space. In the context of this problem, we are tasked with finding the locus of the vertices of a family of parabolas as a parameter \( a \) changes.We determine both the x and y coordinates of the vertex for the parabola equation:
- x-coordinate: \( x = -\frac{3}{4a} \)
- y-coordinate: Substitute \( x = -\frac{3}{4a} \) into the equation to find \( y = -\frac{35a}{16} \)
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, is the study of geometric figures through an algebraic approach using a coordinate system. In this field, we can use algebraic equations to describe geometric shapes and define relationships between points and lines.For parabolas, coordinate geometry allows us to:
- Plot their paths on a Cartesian plane using an equation.
- Find intercepts, slopes, and more complex features like the focus and directrix.
- Analyze and predict how changes in equation parameters (like \( a \) in our parabola) affect the shape's graph.