Chapter 16: Problem 75
\(\int_{0}^{\pi}[\cot x] d x,[\cdot]\) denotes the greatest integer function, is equal to (A) \(\frac{\pi}{2}\) (B) 1 (C) \(-1\) (D) \(-\frac{\pi}{2}\)
Short Answer
Expert verified
The integral evaluates to 0.
Step by step solution
01
Understanding the Problem
The given integral \( \int_{0}^{\pi} [\cot x] \, dx \) involves the greatest integer function, denoted by brackets \([\cdot]\). Our task is to evaluate it over the interval from 0 to \(\pi\). The \([\cot x]\) means we take the integer part (floor) of the \(\cot x\) function. We have to consider the behavior of \(\cot x\) between 0 and \(\pi\).
02
Behavior of \(\cot x\) on the Interval
For \(x \in (0, \pi)\), \(\cot x\) approaches infinity as \(x\) approaches 0 from the right, decreases to 0 as \(x\) approaches \(\frac{\pi}{2}\), and moves towards negative infinity as \(x\) approaches \(\pi\) from the left. The function is undefined at \(x = 0\) and \(x = \pi\).
03
Evaluating the Greatest Integer Function
For \(x \in (0, \frac{\pi}{2})\), \(\cot x > 1\) so \([\cot x] = 1\). For \(x = \frac{\pi}{2}\), \(\cot x = 0\), so \([\cot x] = 0\). For \(x \in (\frac{\pi}{2}, \pi)\), \(\cot x < 0\), leading \([\cot x] = -1\).
04
Splitting the Integral
Split the integral at \(x = \frac{\pi}{2}\): \[\int_{0}^{\pi} [\cot x] \, dx = \int_{0}^{\frac{\pi}{2}} [\cot x] \, dx + \int_{\frac{\pi}{2}}^{\pi} [\cot x] \, dx.\]From previous evaluations: - \([\cot x] = 1\) for \(x \in (0, \frac{\pi}{2})\)- \([\cot x] = -1\) for \(x \in (\frac{\pi}{2}, \pi)\).
05
Calculating Each Integral
Calculate each part: - For the first integral, \(\int_{0}^{\frac{\pi}{2}} 1 \, dx = 1 \times \frac{\pi}{2} = \frac{\pi}{2}\).- For the second integral, \(\int_{\frac{\pi}{2}}^{\pi} (-1) \, dx = -1 \times \left(\pi - \frac{\pi}{2}\right) = -1 \times \frac{\pi}{2} = -\frac{\pi}{2}\).
06
Adding the Integrals
Finally, add the results of the two integrals:\[\frac{\pi}{2} + (-\frac{\pi}{2}) = 0.\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Greatest Integer Function
The greatest integer function, often represented with the notation \([\cdot]\), plays a crucial role in integral calculus when it comes to handling discrete changes of a continuous function. This function essentially takes any real number and "rounds it down" to the nearest integer, known as the floor value. For instance:
- For a value of 3.9, the greatest integer function gives 3.
- If you input -1.2, it outputs -2 since it rounds down negative values as well.
Cotangent Function
The cotangent function, denoted as \(\cot x\), is a trigonometric function which is the reciprocal of the tangent function: \(\cot x = 1/\tan x\). It provides essential insights into angle relationships and measures in trigonometry.
- The cotangent function is particularly noteworthy between \(0 \, \text{and} \, \pi\) where it exhibits distinctive behavior:
- The cotangent function is particularly noteworthy between \(0 \, \text{and} \, \pi\) where it exhibits distinctive behavior:
- As \(x\) approaches 0, \(\cot x\) heads towards infinity.
- It decreases smoothly until \((\pi/2)\), where it becomes zero.
- Beyond \((\pi/2)\), \(\cot x\) shifts to negative values as it asymptotically approaches negative infinity near \(\pi\).
Definite Integration
Definite integration involves calculating the area under a function's curve between two limits. Unlike indefinite integration, which focuses on the antiderivative, definite integration provides a specific numeric result representing the accumulation of quantities.
The process starts by:
The process starts by:
- Identifying integrable segments where the function behaves uniformly, especially important with functions like the step-wise \([\cot x]\) involved here.
- Computing the accumulated area by integrating over each identified segment, as seen in splitting the integral at \(x = \pi/2\).