Chapter 16: Problem 136
If \(I\) is the greatest of the definite integrals \(I_{1}=\int_{0}^{1} e^{-x} \cos ^{2} x d x, I_{2}=\int_{0}^{1} e^{-x^{2}} \cos ^{2} x d x\), \(I_{3}=\int_{0}^{1} e^{-x^{2}} d x\), and \(I_{4}=\int_{0}^{1} e^{-x^{2} / 2} d x\), then, (A) \(I=I_{1}\) (B) \(I=I_{2}\) (C) \(I=I_{3}\) (D) \(I=I_{4}\)
Short Answer
Step by step solution
Compare the Integrals
Analyze Integral I1
Analyze Integral I2
Analyze Integral I3
Analyze Integral I4
Conclusion on Greatest Integral
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponentials in Calculus
- For \(e^{-x}\): The function decreases rapidly from 1 to \(e^{-1}\) over the interval \([0, 1]\).
- For \(e^{-x^2}\): The decay is slower compared to \(e^{-x}\) as \(x^2\) increases slower than \(x\).
- For \(e^{-x^2/2}\): The decay is even less pronounced, as the factor \(-x^2/2\) causes a smaller rate of decrease.
Cosine Functions in Integration
- In \(I_1\), \(\int_{0}^{1} e^{-x} \cos^2 x \, dx\), the rapid decay of the exponential \(e^{-x}\) is coupled with the fluctuating cosine term, creating a complex dynamic.
- In \(I_2\), \(\int_{0}^{1} e^{-x^2} \cos^2 x \, dx\), the slower decay \(e^{-x^2}\) is paired with the cosine fluctuation, leading to a slightly elevated integral value compared to \(I_1\).
Greatest Integral Evaluation
In analyzing integrals, it is crucial to consider the impact of both damping and fluctuation. For example, the integrals \(I_1\) and \(I_2\) include the damping factor of exponential decay and the added complexity of cosine fluctuations, reducing their overall area.
In contrast:
- \(I_3 = \int_{0}^{1} e^{-x^2} \, dx\) lacks cosine fluctuations, offering a steadier integration area.
- \(I_4 = \int_{0}^{1} e^{-x^2/2} \, dx\) not only avoids fluctuations but also features the least decay; it is the least restricted by exponential decay.