Chapter 14: Problem 65
Let \(f\) be \(a\) continuous, diferentiable and bijective function. If the tangent to \(y=f(x)\) at \(x=a\) is also the normal to \(y=f(x)\) at \(x=b\), then there exists at least one \(c \in(a, b)\) such that (A) \(f^{\prime}(c)=0\) (B) \(f^{\prime}(c)>0\) (C) \(f^{\prime}(c)<0\) (D) None of these
Short Answer
Step by step solution
Identify Key Properties
Analyze Tangent Line at \(x = a\)
Analyze Normal Line at \(x = b\)
Set up the Equation
Use Intermediate Value Theorem (IVT)
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Intermediate Value Theorem
This theorem is crucial in proving the existence of a root or a specific value within an interval. It is applicable when you need to find out if a function crosses a particular value within a specific range.
In our exercise, IVT helps confirm that if \( f'(a) \cdot f'(b) = -1 \), then there's a point \( c \) where the derivative \( f'(c) = 0 \). This occurs because the IVT ensures that \( f'(x) \), a continuous function, must pass through all intermediate values between \( f'(a) \) and \( f'(b) \) as it moves from one end of the interval to the other. Thus, if the sign changes, zero is one of those values.
Tangent and Normal Lines
The equation of a tangent line at \( x = a \) can is given by:
- \( y - f(a) = f'(a)(x - a) \)
On the other hand, a normal line is perpendicular to the tangent line at a given point on the curve. This means the slope of the normal line at point \( x = b \) is the negative reciprocal of the slope of the tangent line, which is \(-\frac{1}{f'(b)}\).
In our exercise, the tangent line at \( x = a \) is also the normal line at \( x = b \). Hence we establish the unique condition :
- \( f'(a) = -\frac{1}{f'(b)} \), leading to \( f'(a) \cdot f'(b) = -1 \)
Continuous and Differentiable Functions
A function \( f \) is continuous at a point if the limit of \( f \) as it approaches that point from both directions is the same as the function's value at that point.
Differentiability relates to continuity but adds the requirement that the function's rate of change (slope) is consistent and predictable. This is expressed using derivatives. If a function is differentiable at a point, it is also continuous at that point. However, a function can be continuous but not differentiable.
In the exercise, \( f \) being continuous and differentiable ensures the Intermediate Value Theorem's applicability. It confirms that \( f'(x) \), the derivative, is continuous. Thus, any changes in \( f'(x) \) across interval \((a, b)\) are smooth, allowing us to identify at least one point \( c \) within \((a, b)\) where \( f'(c) = 0 \). This continuity ensures \( f \) does not "jump over" potential roots or slopes.