Chapter 12: Problem 92
Let \(f(x)=x^{4}-8 x^{3}+22 x^{2}-24 x\) and \(g(x)= \begin{cases}\min . f(t) & x \leq t \leq x+1,-1 \leq x \leq 1 \\ x-10 & x>1\end{cases}\) Then, in the interval \([-1, \infty), g(x)\) is (A) continuous for all \(x\) (B) discontinuous at \(x=1\) (C) differentiable for all \(x\) (D) not differentiable at \(x=1\)
Short Answer
Step by step solution
Understand the Functions
Analyze \(f(x)\) over \([-1, 2]\)
Evaluate \(g(x)\) for \([-1, 1]\)
Evaluate \(g(x)\) for \(x > 1\)
Check Continuity at \(x = 1\)
Check Differentiability at \(x = 1\)
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Continuity
- The function must be defined at the point.
- The function must have a limit as it approaches the point from both sides.
- The value of the function at the point must equal its limit as it approaches that point.
Differentiability
Piecewise Functions
- Within \(-1 \leq x \leq 1\), \(g(x)\) is defined by the minimum value of \(f(t)\) over the interval \([x, x+1]\).
- For \(x > 1\), \(g(x)\) switches to the linear function \(x - 10\).