Chapter 12: Problem 53
If \(f(x)=\left\\{\begin{array}{l}x, \text { when } x \text { is rational } \\\ 1-x, \text { when } x \text { is irrational }\end{array}\right.\), then (A) \(f(x)\) is continuous for all real \(x\) (B) \(f(x)\) is discontinuous for all real \(x\) (C) \(f(x)\) is continuous only at \(x=1 / 2\) (D) \(f(x)\) is discontinuous only at \(x=1 / 2\).
Short Answer
Step by step solution
Understanding the Function
Analyzing Continuity at x
Checking Limit from Rational and Irrational Sides
Special Case at x=1/2
Analyzing Other Points for Continuity
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Continuity
- The limit of the function as \( x \) approaches \( c \) must equal the function's value at that point, \( f(c) \).
- The function must be defined at \( x = c \).
Real Numbers
- For rational \( x \), like 1, 0.5, or 3/7, the function directly returns the value \( x \).
- For irrational \( x \), such as \( \pi, \sqrt{2}, \) or \( e, \) the function returns \( 1-x. \)
Limits
Rational Approach
As you approach \( c \) using rational numbers, the function \( f(x) = x \) naturally tends toward \( c \) since it mirrors the rational aspect of \( x \).Irrational Approach
When approaching \( c \) with irrational numbers, the function \( f(x) = 1-x \) moves towards \( 1-c \) since it's based on that form whenever \( x \) is irrational.The effective understanding of limits from both perspectives is crucial to identifying points where the function could be continuous or discontinuous. At \( x = 1/2 \), both approaches yield the same limit \( 1/2 \), indicating continuity there.Discontinuity
- The limit as \( x \) approaches \( c \) through rational numbers results in \( f(x) = c \).
- The limit as \( x \) approaches \( c \) through irrational numbers gives \( f(x) = 1-c \).