Chapter 8: Problem 81
The three successive terms of a G.P. will form the sides of a triangle if the
common ratio \(r\) satisfies the inequality(A)
\(\frac{\sqrt{3}-1}{2}
Short Answer
Expert verified
Option (B) is correct: \( \frac{\sqrt{5}-1}{2}<r<\frac{\sqrt{5}+1}{2} \).
Step by step solution
01
Define the Terms and Condition
Let the three terms of the G.P. be \( a \), \( ar \), \( ar^2 \). For these three terms to form a triangle, the sum of any two sides must be greater than the third side. This gives the triangle inequality properties: \( a + ar > ar^2 \), \( a + ar^2 > ar \), and \( ar + ar^2 > a \).
02
Simplify the First Inequality
The first inequality is \( a + ar > ar^2 \). Factoring out \( a \), we have \( a(1 + r) > ar^2 \). Dividing both sides by \( a \), we get \( 1 + r > r^2 \).
03
Rearrange the First Inequality
Rearrange the inequality \( 1 + r > r^2 \) to \( r^2 - r - 1 < 0 \). This is a quadratic inequality that needs to be solved to find the values of \( r \).
04
Solve the Quadratic Equation
Solve the equation \( r^2 - r - 1 = 0 \) to find the roots. Using the quadratic formula, \( r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = 1 \), \( b = -1 \), \( c = -1 \). This gives the roots \( r = \frac{1 \pm \sqrt{5}}{2} \).
05
Determine the Range of r
The solutions \( \frac{1 - \sqrt{5}}{2} \) and \( \frac{1 + \sqrt{5}}{2} \) determine when the inequality \( r^2 - r - 1 < 0 \) holds. The inequality is satisfied for \( \frac{1 - \sqrt{5}}{2} < r < \frac{1 + \sqrt{5}}{2} \). Since \( \frac{1 - \sqrt{5}}{2} \) is negative, we only consider the positive range: \( 0 < r < \frac{1 + \sqrt{5}}{2} \).
06
Check which Answer Option Fits
Compare the derived range for the inequality \( \frac{1 - \sqrt{5}}{2} < r < \frac{1 + \sqrt{5}}{2} \) with the provided options. The correct range matches option (B), i.e., \( \frac{\sqrt{5}-1}{2} < r < \frac{\sqrt{5}+1}{2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Triangle Inequality
The Triangle Inequality is a fundamental principle in geometry. It states that for any three side lengths to form a triangle, the sum of the lengths of any two sides must be greater than the length of the third side. This ensures that the sides can "close" to form a closed shape, which is a triangle.
To illustrate, consider sides of lengths: \( a \), \( b \), and \( c \). The inequalities can be expressed as:
To illustrate, consider sides of lengths: \( a \), \( b \), and \( c \). The inequalities can be expressed as:
- \( a + b > c \)
- \( a + c > b \)
- \( b + c > a \)
Quadratic Inequality
A quadratic inequality involves a quadratic expression which needs to be solved to find ranges or intervals. Solving these inequalities involves understanding how the quadratic equation behaves with different values:
Let's consider a quadratic inequality in the form of \( ax^2 + bx + c < 0 \). Here's how to solve it:
Let's consider a quadratic inequality in the form of \( ax^2 + bx + c < 0 \). Here's how to solve it:
- First, find the roots of the corresponding quadratic equation \( ax^2 + bx + c = 0 \). This can be done using the quadratic formula, \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
- Utilize these roots to divide the number line into intervals. You'll check the sign of the quadratic in each interval to see where the inequality is satisfied.
- The inequality's solution will usually lie between the roots where the parabola opens upwards and below the x-axis. Conversely, for \( ax^2 + bx + c > 0 \), the solution will be outside these roots.
Roots of a Quadratic Equation
Finding the roots of a quadratic equation is essential in understanding and solving problems related to quadratic inequalities. The roots determine the points where the quadratic function crosses the x-axis.
A quadratic equation takes the form \( ax^2 + bx + c = 0 \). The roots can be found using the quadratic formula:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
Here, \( b^2 - 4ac \) is called the discriminant, which determines the nature of the roots. If:
A quadratic equation takes the form \( ax^2 + bx + c = 0 \). The roots can be found using the quadratic formula:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
Here, \( b^2 - 4ac \) is called the discriminant, which determines the nature of the roots. If:
- The discriminant is positive, there are two distinct real roots.
- It is zero, indicating one real root (a repeated root).
- It is negative, suggesting two complex roots.