Chapter 4: Problem 81
If \(\alpha, \beta\) are the roots of the equation \(a x^{2}+b x+c=0\), \((a \neq 0)\) and \(\alpha+\delta, \beta+\delta\) are the roots of \(A x^{2}+B x+\) \(C=0,(A \neq 0)\) for some constant \(\delta\), then (A) \(\frac{b^{2}-4 a c}{a^{2}}=\frac{B^{2}-4 A C}{A^{2}}\) (B) \(\frac{b^{2}-2 a c}{a^{2}}=\frac{B^{2}-2 A C}{A^{2}}\) (C) \(\frac{b^{2}-8 a c}{a^{2}}=\frac{B^{2}-8 A C}{A^{2}}\) (D) None of these
Short Answer
Step by step solution
Identify Known Values
Utilize Vieta's Formulas for Equation 1
Apply Vieta's Formulas to Equation 2
Express Sums and Products of Roots
Establish Relations between Coefficients
Find Product Relationships
Solve for Discriminant Formula
Verify Options Against Step 7 Solution
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vieta's Formulas
- \( \alpha + \beta = -\frac{b}{a} \)
- \( \alpha\beta = \frac{c}{a} \)
Discriminants of Quadratic Equations
- If the discriminant is positive, there are two distinct real roots.
- If it is zero, there is exactly one real root (also known as a repeated root).
- If the discriminant is negative, there are no real roots, but two complex roots.