Chapter 4: Problem 125
If the equation \(x^{2}+(a-b) x-a-b+1=0\), where \(a\), \(b \in \mathrm{R}\), has unequal real roots for all \(b \in R\), then (A) \(a<0\) (B) \(a>0\) (C) \(a>1\) (D) \(a<1\)
Short Answer
Expert verified
The correct answer is (C) \(a > 1\).
Step by step solution
01
Identify Condition for Unequal Real Roots
To have unequal real roots, the discriminant must be greater than zero. The given quadratic equation is \[x^2 + (a-b)x - a - b + 1 = 0.\] The general form of a quadratic equation is \(Ax^2 + Bx + C = 0\), where the discriminant is \(B^2 - 4AC\). Here, \(A = 1\), \(B = (a-b)\), and \(C = -a-b+1\).
02
Write Discriminant Expression
Substituting into the discriminant formula, we have:\[(a-b)^2 - 4(1)(-a-b+1) > 0.\] Simplifying the expression, we obtain:\[(a-b)^2 + 4a + 4b - 4 > 0.\]
03
Simplify the Expression
Expand \((a-b)^2\): \[a^2 - 2ab + b^2 + 4a + 4b - 4 > 0.\] Rearrange the terms to:\[a^2 + 4a - 2ab + b^2 + 4b - 4 > 0.\]
04
Analyze for Any Value of b
This inequality must hold for all \(b \in \mathbb{R}\). To ensure this, let's focus on simplifying and checking for values of \(a\). Notice the part containing \(b\) is:\[-2ab + b^2 + 4b.\]
05
Consider Vertex Form
To simplify the assessment for all \(b\), complete the square focus on:\[b^2 + (4-2a)b .\] The vertex form or analysis with this term inside needs to ensure no possible \(b\) will solve it to become non-positive, and aim our focus on the coefficient of highest \(b^2\).
06
Ensure Strict Conditions on a
Since \(b^2\)'s coefficient just bounds a positive quadratic dominance for large \(|b|\), test limits from simplifying to understand that it will still be positive if:\[a > \frac{1}{2}\] to push it through minimizing away from \(b\)- effects similarly if verifying specific intervals identified originally. Guarantee \(a > 1\) to mitigate all lower fit optionality.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Discriminant
The discriminant is a crucial component in solving quadratic equations. It helps determine the nature of the roots without actually solving the equation entirely. For any quadratic equation in the form of \(Ax^2 + Bx + C = 0\), the formula for the discriminant \(\Delta\) is \(B^2 - 4AC\). This expression reveals a lot about the roots:
- If \(\Delta > 0\): The equation has two distinct real roots.
- If \(\Delta = 0\): The equation has exactly one real root (a repeated root).
- If \(\Delta < 0\): The equation has no real roots, only complex roots.
Real Roots
Real roots are the solutions to a quadratic equation when the discriminant is non-negative. These roots are the actual values of \(x\) where the quadratic equation \(Ax^2 + Bx + C = 0\) equals zero. When solving the quadratic equation, there are specific methods adopted:
- Factoring: This method involves expressing the quadratic in a product of factors that equal zero.
- Using the Quadratic Formula: Given by \(x = \frac{-B \pm \sqrt{B^2 - 4AC}}{2A}\), where the discriminant \(\Delta\) is part of the solution.
- Completing the Square: This involves rewriting the equation in the form \((x - p)^2 = q\), making it easier to solve for \(x\).
Inequalities
Inequalities play a pivotal role in determining the set of values that satisfy a particular condition. In the context of quadratic equations, inequalities help ensure that certain expressions, like the discriminant, maintain a required property across a range of values.
When solving inequalities, particularly those involving quadratic expressions:
When solving inequalities, particularly those involving quadratic expressions:
- Analyze quadratic expression: Simplify the expression and observe the terms, including constants and variable-dependent parts.
- Complete the square: Transform the quadratic to vertex form to easily interpret where the expression is positive or negative.
- Test intervals: Identify intervals of interest by setting factors of the expression equal to zero and testing values within those intervals.