Chapter 3: Problem 104
The value of the expression \((\omega-1)\left(\omega-\omega^{2}\right)\left(\omega-\omega^{3}\right)\) ... \(\left(\omega-\omega^{n-1}\right)\), where \(w\) is the \(n^{\text {th }}\) root of unity, is (A) \(n \omega^{n-1}\) (B) \(n \omega^{n}\) (C) \((n-1) \omega^{n}\) (D) \((n-1) \omega^{n-1}\)
Short Answer
Step by step solution
Understanding the Problem
Identifying Roots of Unity Properties
Simplication of the Expression
Evaluating the Polynomial at \(x = \omega\)
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomial Evaluation
- The expression \((\omega-1)(\omega-\omega^2)(\omega-\omega^3) \ldots (\omega-\omega^{n-1})\) is essentially the polynomial \((x-1)(x-\omega)(x-\omega^2)\ldots(x-\omega^{n-1})\) evaluated at \(x = \omega\).
- This substitution means replacing \(x\) with \(\omega\) in all terms.
- The key factor \( (\omega - \omega) \) equals \(0\), and the product of any expression containing a factor of 0 is necessarily 0.
Product of Roots
- Roots of unity are special because, for the polynomial \(x^n - 1\), they include all complex solutions to the equation \(x^n = 1\).
- This polynomial can be factored as \((x-1)(x-\omega)(x-\omega^2)\ldots(x-\omega^{n-1})\).
- Our exercise involved evaluating the product at the specific root \(x = \omega\), which contained all the terms except for \((x-\omega)\).
Complex Numbers
- Each \(n\)-th root of unity is a complex number expressed in the form \(\omega = e^{2\pi i k/n}\) for \(k = 0, 1, 2, \ldots, n-1\).
- The real and imaginary parts of these roots can be plotted on the complex plane, forming a regular polygon.
- This representation helps visualize how roots of unity relate to polynomial solutions, especially evaluating and simplifying expressions where real numbers alone are insufficient.