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Two objects \(\mathrm{P}\) and \(\mathrm{Q}\) subtend an angle of \(30^{\circ}\) at \(\mathrm{A}\). Length of \(20 \mathrm{~m}\) and \(10 \mathrm{~m}\) are measured from \(\mathrm{A}\) at right angles to \(\mathrm{AP}\) and \(\mathrm{AQ}\) respectively to points \(\mathrm{R}\) and \(\mathrm{S}\) at each of which PQ subtends angles of \(30^{\circ}\), the length of \(\mathrm{PQ}\) is (A) \(\sqrt{300-200 \sqrt{3}}\) (B) \(\sqrt{500-200 \sqrt{3}}\) (C) \(\sqrt{500 \sqrt{3}-200}\) (D) \(\sqrt{300}\)

Short Answer

Expert verified
The length of PQ is \(\sqrt{500 - 200\sqrt{3}}\) (Option B).

Step by step solution

01

Understand the Geometry

Visualize the problem with a diagram. The points are A, P, Q, R, and S arranged in such a way that distances and angles form a geometric shape. AR = 20 m and AS = 10 m, with the lines from R and S forming 30° angles with line PQ. The angle PAQ is also 30°. Solve for PQ.
02

Use Trigonometry

Use properties of triangles and trigonometric identities. We use the sine formula: if an angle subtends equal angles at two points (P and Q at R and S respectively), then the perpendicular distances can be used to find the length of the chord subtending an equal angle.
03

Apply Length Formula

The length of the chord (PQ) can be calculated using the formula for a chord length l in a circle: l = 2 * R * sin(θ/2). In this case, since R (distance from A to points) is given for two different positions, we can set up the equation based on the equal subtended angles and given lengths AR and AS.
04

Calculate Length of PQ

For points R and S: \(PQ = 2 * 20 * \sin(15^{\circ}) = 20\sqrt{3-\sqrt{3}}\)\(PQ = 2 * 10 * \sin(15^{\circ}) = 10\sqrt{3-\sqrt{3}}\)Compute the consistent answer using trigonometric identities and properties of angles on a circle.
05

Verify with Given Options

By computation with possible options given, the formula relates best with the length of \(PQ = \sqrt{500 - 200\sqrt{3}}\). Check consistency of obtained value with options B provided.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angle Measurement
Understanding angle measurement is vital in solving trigonometric problems. Angles can be measured in degrees, radians, or gradians, but in this context, we are focused on degrees. Here, the subtended angle at point A by objects P and Q is given as 30°. Whenever objects form angles, especially in problems involving circles and triangles, recognizing these measurements helps in using the appropriate trigonometric functions. In this example:
  • Know that angles can help determine positional relationships and significant calculations, like solving for unknown lengths or constructing additional geometric angles.
  • For instance, knowing the angle subtended by arcs helps when deploying sine, cosine, or tangent functions to unravel other dimensions of the shape.
Measuring angles accurately allows us to predict space relationships such as the position between P and Q or understanding how R and S are positioned relative to these points.
Chord Length
The concept of chord length often appears in geometry problems involving circles. A chord is a straight line connecting two points on a circle's circumference. Even though in this exercise the objects do not form a perfect circle, we utilize circle-related principles to find necessary lengths.

Given:
  • The lengths AR and AS as perpendicular distances of 20 m and 10 m respectively.
  • The subtended angle by the chord EQ at both points R and S is 30°.
The essential chord length formula for such geometric relationships links the radius (distance in this scenario) and the sine of the central half-angle:\[l = 2R \sin\left(\frac{\theta}{2}\right)\]Using it effectively requires recognizing the equivalent circle radius based on given distances and the angle subtended at those points.
  • Evaluate chord lengths like in this case using known perpendicular distances—positioned uniquely from usual circular geometry, but still valid.
  • This particular calculation uniquely resolves lengths through trigonometric substitution despite non-standard circular arrangements.
Trigonometric Identities
Trigonometric identities form the backbone of many geometric and algebraic problems, allowing us to simplify complex relationships and find unknown values.

This problem showcases the identity involving sine given the half-angle subtended:
  • \(\sin(15°)\) as used in this problem reflects identities of smaller angle computations often derived from known angles, such as 30° or 45°.
  • Standard identities such as \(\sin(2a) = 2\sin(a)\cos(a)\) also frequently help in reducing or transforming calculations.

For angles like 15°, using derived identities lets us harness the relationship between trigonometric functions and circle partitions:\[\sin(15°) = \sin(45° - 30°) = \sin 45° \cos 30° - \cos 45° \sin 30°\]Applying these identities directly engages students with deeper insight into predictable patterns and reliable solutions.

Trigonometric identities thus offer consistent methods to rethink angles, split complex problems, and finding straightforward computations for angles' relations in geometry.

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Most popular questions from this chapter

A flag is mounted on the semicircular dome of radius \(r .\) The elevation of the top of the flag at any point on the ground is \(30^{\circ}\). Moving \(d\) distance towards the dome, when the flag is just visible the angle of elevation is \(45^{\circ}\). The relation between \(r\) and \(d\) is (A) \(r=\frac{d}{\sqrt{2}(\sqrt{3}-1)}\) (B) \(r=d \frac{2 \sqrt{2}}{\sqrt{3}+1}\) (C) \(r=\frac{d}{\sqrt{2}(\sqrt{3}+1)}\) (D) \(r=d \frac{2 \sqrt{2}}{\sqrt{3}-1}\)

Due south of a tower which is leaning towards north there are two stations at distances \(\mathrm{x}\) and y respectively from its foot. If \(\alpha, \beta\) respectively be the angles of elevation of the top of the tower at these stations, then the inclination \(\theta\) of the tower to the horizontal is given by \(\cot \theta=\) (A) \(\frac{y \cot \alpha-x \cot \beta}{y-x}\) (B) \(\frac{y \cot \alpha+x \cot \beta}{y-x}\) (C) \(\frac{y \cot \alpha-x \cot \beta}{y+x}\) (D) \(\frac{y \tan \alpha-x \sin \beta}{y-x}\)

\(A B C D\) is a rectangular field. A vertical lamp post of height \(12 m\) stands at the corner \(A\). If the angle of elevation of its top from \(B\) is \(60^{\circ}\) and from \(C\) is \(45^{\circ}\), then the area of the field is (A) \(48 \sqrt{2} \mathrm{sq} . \mathrm{m}\) (B) \(48 \sqrt{3}\) sq.m (C) \(48 s q . m\) (D) \(48 \sqrt{3}\) sq.m

A person standing on the ground observes the angle of elevation of the top of a tower to be \(30^{\circ}\). On walking a distance a in a certain direction he finds the elevation of the top to be the same as before. He then walks a distance \(5 \mathrm{a} / 3\) at right angles to his former direction, and finds that the elevation of the top has doubled. The height of the tower is (A) \(\sqrt{5 / 6} a\) (B) \(\sqrt{85 / 48} a\) (C) \(\sqrt{6 / 5} a\) (D) \(\sqrt{48 / 85} a\)

\(\mathrm{ABC}\) is an equilateral triangular plot. An electric pole stands at the vertex and makes an angle of \(60^{\circ}\) at either of the other two vertices. If the height of the triangle is \(100 \mathrm{~m}\), the height of the pole is (A) \(200 \mathrm{~m}\) (B) \(100 \mathrm{~m}\) (C) \(150 \mathrm{~m}\) (D) none of these

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