Chapter 24: Problem 106
Plant I of \(X Y Z\) manufacturing organization employs 5 production and 3 maintenance foremen, another plant II of same organization employs 4 production and 5 maintenance foremen. From any one of these plants, a single selection of two foremen is made. The probability that one of them would be production and the other maintenance foreman is (A) \(\frac{275}{504}\) (B) \(\frac{263}{504}\) (C) \(\frac{301}{504}\) (D) \(\frac{362}{504}\)
Short Answer
Step by step solution
Identify the Total Combinations
Identify Favorable Combinations from Plant I
Identify Favorable Combinations from Plant II
Calculate Total Favorable Combinations
Calculate Probability
Final Calculation and Conclusion
Matching with Given Option
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Combination Formula
Probability Calculation
Combinatorial Selection
- Select 1 out of 5 production foremen: 5 ways
- Select 1 out of 3 maintenance foremen: 3 ways