Chapter 21: Problem 100
Let \(\vec{a}=\vec{j}-\vec{k}\) and \(\vec{c}=\vec{i}-\vec{j}-\vec{k}\). Then, the vector \(\vec{b}\) satisfying \(\vec{a} \times \vec{b}+\vec{c}=\overrightarrow{0}\) and \(a \cdot \vec{b}=3\) is (A) \(2 \hat{i}-\hat{j}+2 \hat{k}\) (B) \(\hat{i}-\hat{j}-2 \hat{k}\) (C) \(\hat{i}+\hat{j}-2 \hat{k}\) (D) \(-\hat{i}+\hat{j}-2 \hat{k}\)
Short Answer
Step by step solution
Understanding the Problem
Express the Cross Product Equation
Calculate \( \vec{a} \times \vec{b} \)
Equate Components for Cross Product
Solve Dot Product Condition
Verify and Select the Correct Option
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
To find the cross product, you can use the determinant of a matrix constructed with unit vectors \( \hat{i}, \hat{j}, \hat{k} \) in the first row and the components of each vector in the subsequent rows. For example:
\[ \vec{a} \times \vec{b} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \ a_1 & a_2 & a_3 \ b_1 & b_2 & b_3 \end{vmatrix} \]
Where \( \vec{a} = a_1 \hat{i} + a_2 \hat{j} + a_3 \hat{k} \) and \( \vec{b} = b_1 \hat{i} + b_2 \hat{j} + b_3 \hat{k} \). The result is a vector that:
- Has components calculated as follows: \( \vec{a} \times \vec{b} = (a_2b_3 - a_3b_2)\hat{i} - (a_1b_3 - a_3b_1)\hat{j} + (a_1b_2 - a_2b_1)\hat{k} \).
Dot Product
\[ \vec{a} \cdot \vec{b} = a_1b_1 + a_2b_2 + a_3b_3 \]
This formula emerges from analyzing each component's product and summing them. The result, a single number, reveals:
- When \( \vec{a} \cdot \vec{b} = 0 \), the vectors are orthogonal, hinting at no "shared directionality."
- How much of one vector "extends in the direction of" another, providing nuances about their alignment.
Component Form
When expressed in component form, a vector crystallizes into a sum of these axis-aligned contributions. For instance, a vector \( \vec{v} \) in component form reads as \( \vec{v} = v_1\hat{i} + v_2\hat{j} + v_3\hat{k} \), where:
- \( v_1 \), \( v_2 \), and \( v_3 \) capture the magnitudes along each axis.
- This setup allows effortless interaction of vectors, aiding calculations like addition, subtraction, and those involving dot or cross products.