Chapter 17: Problem 77
For a certain curve \(y=f(x)\) satisfying \(\frac{d^{2} y}{d x^{2}}=6 x-4\), \(f(x)\) has a local minimum value 5 when \(x=1\). (A) Equation of the curve is \(y=x^{3}-2 x^{2}+x+5\) (B) \(f(x)\) has a local maximum at \(x=\frac{1}{3}\) (C) Global maximum value of \(f(x)\) is 7 (D) Global minimum value of \(f(x)\) is 5
Short Answer
Step by step solution
Integrate Second Derivative
Use Local Minimum Condition
Determine First Derivative
Find Original Function
Write Equation of the Curve
Analyze Local Maximum
Determine Global Max/Min Values
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Second Derivative Test
- If the second derivative at this point is positive (\(f''(x) > 0\)), the function has a local minimum there.
- If the second derivative at this point is negative (\(f''(x) < 0\)), the function has a local maximum.
- If the second derivative is zero (\(f''(x) = 0\)), the test is inconclusive, and higher-derivative tests or alternative methods might be needed.
Local Minimum and Maximum
In the context of a problem where \(f(x)\) has a local minimum at \(x = 1\), the derivative \(f'(x)\) equals zero at this point. Checking the second derivative helps confirm this as a minimum since \(f''(1)\) would be positive. Conversely, for a local maximum at \(x = \frac{1}{3}\), you verify it by confirming \(f''\left(\frac{1}{3}\right)\) is negative.
Local extrema are essential in optimization problems and are helpful in sketching graphs, analyzing growth trends, and more.
Cubic Polynomial
They are crucial in modeling real-world scenarios and visualizing dynamic processes. Analyzing a cubic polynomial involves finding its roots, determining its end behavior, and understanding the turning points.
- The polynomial \(y = x^3 - 2x^2 + x + 5\) is a specific cubic example.
- It has both linear components affecting the slope and a cubic shape influencing the curve’s asymmetry.
Integration Techniques
Common techniques include:
- Integration by Substitution: Useful for simplifying functions before integrating.
- Integration by Parts: Specifically beneficial when dealing with products of functions.
- Partial Fractions: Breaking complex fractions into simpler parts that are easier to integrate.