Chapter 12: Problem 50
\(f(x)=\left\\{\begin{array}{cc}\frac{e^{[x]+|x|}-2}{[x]+|x|}, & x \neq 0 \\\ -1, & x=0\end{array},([.]\right.\) denotes the greatest integer function), then (A) \(f(x)\) is continuous at \(x=0\) (B) \(\lim _{x \rightarrow 0^{-}} f(x)=-1\) (C) \(\lim _{x \rightarrow 0^{-}} f(x)=1\) (D) None of these
Short Answer
Step by step solution
Understand the Problem
Evaluate Case When \( x = 0 \)
Explore \( \\lim_{x \rightarrow 0^{+}} f(x) \)
Explore \( \\lim_{x \rightarrow 0^{-}} f(x) \)
Determine Continuity at \( x = 0 \)
Identify the Correct Statement
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limit of a function
- A two-sided limit exists if both one-sided limits exist and are equal.
- The two-sided limit of a function at a point is a pivotal factor in determining the function's continuity at that point.
For the function \( f(x) \), we calculated \lim_{x \to 0^+} f(x) = 1 and \lim_{x \to 0^-} f(x) = 2 - \frac{1}{e}. These are not equal, which leads to the conclusion that the overall limit does not exist at \( x = 0 \). This explains why \( f(x) \) is discontinuous at \( x = 0 \), as a function must have an equal two-sided limit at a point to be continuous there.
Greatest integer function
- If \( x \) is a positive number, \([x]\) gives the integer part of \( x \). For example, if \( x = 2.9 \), then \([x] = 2\).
- If \( x \) is a negative number, \([x]\) is the first integer that is less than \( x \). For example, if \( x = -1.3 \), then \([x] = -2\).
In this problem, when we looked at \( x \to 0^+ \), we found that \([x] = 0\); and for \( x \to 0^- \), we had \([x] = -1\). These played a crucial role in breaking down the function into separate cases for determining the limits as \( x \to 0 \). The property of taking a sudden leap at integer values makes the greatest integer function special and sometimes complex to handle in continuous and differentiable contexts.
Absolute value function
- \( |x| = x \) if \( x \ge 0 \)
- \( |x| = -x \) if \( x < 0 \)
This piecewise nature allows the absolute value function to transform the input into a purely positive form or zero. It plays a key role in analyzing distances and can introduce non-linear behavior into functions.In the exercise, the absolute value function was crucial when examining \( f(x) \) as \( x \) approached zero. For \( x \rightarrow 0^+ \), we found that |x| = x. For \( x \rightarrow 0^- \), we determined |x| = -x. Each adjusted the value of the function accordingly, impacting the limits from the left and right, and thus the overall continuity evaluation.