Chapter 23: Problem 2
Solve each of the following pairs of simultaneous congruences: (a) \(10 x \equiv 2(\bmod 12) ; 6 x \equiv 14(\bmod 20)\) (b) \(4 x \equiv 2(\bmod 6) ; 9 x \equiv 3(\bmod 12)\) (c) \(6 x \equiv 2(\bmod 8) ; 10 x \equiv 2(\bmod 12)\)
Short Answer
Expert verified
(a) x = 29, (b) x = 11, (c) x = 23
Step by step solution
01
Simplify the First Congruence (Part a)
For the congruence \(10x \equiv 2 \pmod{12}\), simplify by dividing all terms by the greatest common divisor (GCD) of 10, 2, and 12, which is 2. This simplifies to \(5x \equiv 1 \pmod{6}\).
02
Simplify the Second Congruence (Part a)
For \(6x \equiv 14 \pmod{20}\), first solve the equation. Since \( \gcd(6, 20) = 2 \), divide the entire congruence by 2, resulting in \(3x \equiv 7 \pmod{10}\).
03
Solve the First Simplified Congruence (Part a)
Solve \(5x \equiv 1 \pmod{6}\). To find the inverse of 5 modulo 6, note that \(5 \equiv -1 \pmod{6}\) so \(5 \times 5 \equiv 25 \equiv 1 \pmod{6}\). Thus, the solution is \(x \equiv 5 \pmod{6}\).
04
Solve the Second Simplified Congruence (Part a)
For \(3x \equiv 7 \pmod{10}\), try values for \(x\) to satisfy the equation. If \(x = 9\), then \(3 \times 9 = 27 \equiv 7 \pmod{10}\). Therefore, \(x \equiv 9 \pmod{10}\).
05
Apply the Chinese Remainder Theorem (Part a)
To solve \(x \equiv 5 \pmod{6}\) and \(x \equiv 9 \pmod{10}\), note that 6 and 10 are coprime but overlap because of the solution values. Testing \(x = 29\) satisfies both: \(29 \equiv 5 \pmod{6}\) and \(29 \equiv 9 \pmod{10}\).
06
Solve the First Congruence (Part b)
For \(4x \equiv 2 \pmod{6}\), divide through by the GCD, 2, resulting in \(2x \equiv 1 \pmod{3}\). Since 2 is invertible modulo 3, and its inverse is 2, \(x \equiv 2 \pmod{3}\).
07
Solve the Second Congruence (Part b)
Simplify \(9x \equiv 3 \pmod{12}\) by noting \( \gcd(9, 12) = 3\). Dividing by 3 gives \(3x \equiv 1 \pmod{4}\), and testing \(x = 3\), the solution \(x \equiv 3 \pmod{4}\) satisfies it.
08
Apply the Chinese Remainder Theorem (Part b)
To solve \(x \equiv 2 \pmod{3}\) and \(x \equiv 3 \pmod{4}\), use back substitution to find \(x = 11\), which meets both congruences: \(11 \equiv 2 \pmod{3}\) and \(11 \equiv 3 \pmod{4}\).
09
Solve the First Congruence (Part c)
Simplify \(6x \equiv 2 \pmod{8}\) by dividing everything by 2 (the GCD of 6, 2, and 8), to get \(3x \equiv 1 \pmod{4}\). Test and find \(x = 3\) gives: \(3 \times 3 = 9 \equiv 1 \pmod{4}\), so \(x \equiv 3 \pmod{4}\).
10
Solve the Second Congruence (Part c)
For \(10x \equiv 2 \pmod{12}\), simplify by finding the GCD, which is 2, to yield \(5x \equiv 1 \pmod{6}\). Using the reciprocal method, the inverse is 5, giving \(x \equiv 5 \pmod{6}\).
11
Apply the Chinese Remainder Theorem (Part c)
To find a common solution for \(x \equiv 3 \pmod{4}\) and \(x \equiv 5 \pmod{6}\), compute through substitution; trial and error reveals \(x = 23\) satisfies all the conditions: \(23 \equiv 3 \pmod{4}\) and \(23 \equiv 5 \pmod{6}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chinese Remainder Theorem
The Chinese Remainder Theorem is a classic method used when dealing with simultaneous congruences, particularly when the moduli are pairwise coprime (meaning they share no common factor other than 1). This theorem allows us to find a unique solution modulo the product of the moduli. In essence, if you have two or more congruences:
- \( x \equiv a \pmod{m} \)
- \( x \equiv b \pmod{n} \)
greatest common divisor (GCD)
The greatest common divisor (GCD) is a fundamental concept in number theory, deeply intertwined with congressive solutions. It defines the largest integer that can divide two or more numbers without leaving a remainder. This concept is crucial when simplifying congruences and solving modular problems.
- For instance, when solving \( 10x \equiv 2 \pmod{12} \), the GCD of 10, 2, and 12 is key.
- The GCD helps in reducing the terms, by dividing them out, simplifying the equation to \( 5x \equiv 1 \pmod{6} \).
modular arithmetic
Modular arithmetic, sometimes known as 'clock arithmetic', is a system of arithmetic for integers, where numbers wrap around a certain value—the modulus. This means that the numbers reset after reaching this modulus, much like how the numbers on a clock reset after going past 12.
- In modular arithmetic, equivalence is expressed as
\( a \equiv b \pmod{m} \), meaning when \( a \) is divided by \( m \), it leaves the same remainder as \( b \). - In the example of \( 6x \equiv 2 \pmod{8} \), you simplify this by realizing that the numbers loop every 8.