Chapter 22: Problem 9
Let \(\operatorname{gcd}(a, b)=c\) and \(\operatorname{lcm}(a, b)=d .\) Then \(c d=a b\).
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Chapter 22: Problem 9
Let \(\operatorname{gcd}(a, b)=c\) and \(\operatorname{lcm}(a, b)=d .\) Then \(c d=a b\).
These are the key concepts you need to understand to accurately answer the question.
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If \(\operatorname{gcd}(a b, c)=1\), then \(\operatorname{gcd}(a, c)=1\) and \(\operatorname{gcd}(b, c)=1\)
Let \(d=\operatorname{gcd}(a, b)\). For any integer \(x, d \mid x\) iff \(x\) is a linear combination of \(a\) and \(b\).
If \(\operatorname{gcd}(a, b)=d\), then \(\langle a\rangle+\langle b\rangle=\langle d\rangle .\) (NOTE: If \(J\) and \(K\) are ideals of a ring \(A\) len \(J+K=\\{x+y: x \in J\) and \(y \in K\\} .)\)
If \(a \mid b\) and \(b \mid c\), then \(a \mid c\)
* and \(\circ\) are associative.
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