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Let \(G, H\), and \(K\) be groups. Prove the following: The function \(f: G \rightarrow G\) defined by \(f(x)=x^{2}\) is a homomorphism iff \(G\) is abelian.

Short Answer

Expert verified
The function is a homomorphism if and only if group \( G \) is abelian.

Step by step solution

01

Understand Homomorphism

A function \( f: G \rightarrow G \) is a homomorphism if for all elements \( a, b \in G \), the equation \( f(ab) = f(a)f(b) \) holds. This means applying \( f \) to a product in the group must equal the product of applying \( f \) to each element separately.
02

Function Representation

Given \( f(x) = x^2 \), for any elements \( a, b \in G \), the equation becomes \( f(ab) = (ab)^2 \) and \( f(a)f(b) = a^2b^2 \). The function is a homomorphism if \( (ab)^2 = a^2b^2 \) for all \( a, b \in G \).
03

Expand Condition for Homomorphism

The condition for homomorphism \((ab)^2 = a^2b^2\) can be expanded as \( ab \, ab = a^2b^2 \). By associativity in groups, this becomes \( a(ba)b = a^2b^2 \).
04

Examine for Abelian Property

The equation \( a(ba)b = a^2b^2 \) holds if and only if \( ab = ba \) for all \( a, b \in G \). This is precisely the definition of an abelian group: the elements commute, meaning the group operation is commutative.
05

Conclude Homomorphism Condition

Therefore, the function \( f(x) = x^2 \) is a homomorphism if \( ab = ba \) for all \( a, b \), which implies \( G \) is abelian. Conversely, if \( G \) is abelian, then \( (ab)^2 = a^2b^2 \) automatically holds as each element commutes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Homomorphism
A homomorphism is a fundamental concept in group theory where it refers to a function between two groups that preserves the group operation. Imagine you have a group, say, a set of objects that can be combined in a specific way. A homomorphism acts as a bridge between two such groups, ensuring that the way you combine things in the first group carries over correctly to the second group. This translates into the mathematical requirement that for any two elements \(a\) and \(b\) in a group \(G\), the homomorphism \(f\) satisfies the equation \(f(ab) = f(a)f(b)\).

Here are some key points to remember about homomorphisms:
  • The function maintains the structure of the group, meaning products in \(G\) remain consistent in \(f(G)\).
  • A homomorphism does not necessarily mean the groups are identical, but it does mean their operation properties are maintained.
  • Understanding how homomorphisms work can help you see the relationships between different algebraic structures.
Abelian Group
An Abelian group is a type of group where the order in which you perform an operation does not matter. This means any two elements \(a\) and \(b\) in an Abelian group \(G\) satisfy the equation \(ab = ba\). This property is also known as commutativity. If you think about day-to-day operations like addition, you'll see that this is often intuitive: adding 3 + 5 gives the same result as 5 + 3.

Here are some important aspects of Abelian groups:
  • Commutativity is the defining feature that sets them apart from other groups.
  • The structure simplifies many mathematical operations and properties, such as solving equations.
  • Examples include the group of integers with addition as the operation, as well as the real numbers.
When dealing with group theory, identifying an Abelian group can often make solving problems easier due to its straightforward nature.
Group Operation
The group operation in mathematics defines how two elements from a group combine to form another element within the same group. This operation, which could be addition, multiplication, or any similar process, must satisfy certain properties: closure, associativity, identity, and invertibility. These properties are what make up the foundational definition of a group.

Key properties of group operations include:
  • Closure: If you take any two elements from the group and apply the operation, the result is still an element within the group.
  • Associativity: The way in which the elements are grouped does not affect the outcome of the operation: \((ab)c = a(bc)\).
  • Identity Element: There exists an element in the group that, when used in the operation, leaves other elements unchanged.
  • Inverse Element: For every element in the group, there is another element that combines with it to produce the identity element.
Understanding the group operation is crucial to analyzing any group structure, as it inherently plots the roadmap for interactions within the group.
Homomorphism Condition
The homomorphism condition is a crucial aspect when determining whether a function between two groups is indeed a homomorphism. Specifically, this condition requires that applying the function to the group operation of two elements should equal applying the function to each element separately, and then combining results using the group operation in the target group.

Let's break down how the homomorphism condition is verified:
  • Given a function \(f: G \rightarrow G\) and a group operation \(\ast\) in group \(G\), verify that \(f(a \ast b) = f(a) \ast f(b)\) for all elements \(a\) and \(b\).
  • If a function satisfies this condition, it retains the structure and rules of combining elements from one group to another.
  • In the context of the problem, checking if \((ab)^2 = a^2b^2\) helps to confirm whether the function \(f(x) = x^2\) is a homomorphism, which links it directly to the structure of the group being Abelian.
The homomorphism condition ensures that even if the elements themselves change from one group to another, the way they interact does not.

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Most popular questions from this chapter

Imagine a square as a piece of paper lying on a table. The side facing you is side A. The side hidden from view is side \(B\). Every motion of the square either inter- changes the two sides (that is, side \(B\) becomes visible and side \(A\) hidden) or leaves the sides as they were. In other words, every motion \(R_{i}\) of the square brings about one of the permutations $$ \left(\begin{array}{ll} A & B \\ A & B \end{array}\right) \quad \text { or } \quad\left(\begin{array}{ll} A & B \\ B & A \end{array}\right) $$ of the sides; call it \(g\left(R_{i}\right)\). Verify that \(g: D_{4} \rightarrow S_{2}\) is a homomorphism, and give its kernel.

Prove that each of the following is a homomorphism, and describe its kernel. Let \(G\) be the multiplicative group of all \(2 \times 2\) matrices $$ \left(\begin{array}{ll} a & b \\ c & d \end{array}\right) $$ satisfying \(a d-b c \neq 0\). Let \(f: G \rightarrow \mathbb{R}^{*}\) be given by \(f(A)=\) determinant of \(A=a d-b c\)

Let \(G\) denote a group, and \(H\) a subgroup of \(G\). Prove the following: In a group \(G\), a commutator is any product of the form \(a b a^{-1} b^{-1}\), where \(a\) and \(b\) are any elements of \(G .\) If a subgroup \(H\) of \(G\) contains all the commutators of \(G\), then \(H\) is normal.

Let \(H\) be a subgroup of \(G\). For any \(a \in G\), let \(a H a^{-1}=\left\\{a \times a^{-1}: x \in H\right\\} ; a H a^{-1}\) is called a conjugate of \(H .\) Prove the following: \(H\) is a normal subgroup of \(G\) iff \(H=a H a^{-1}\) for every \(a \in G\). In the remaining exercises of this set, let \(G\) be a finite group. By the normalizer of \(H_{1}\) we mean the set \(N(H)=\left\\{a \in G: a x a^{-1} \in H\right.\) for every \(\left.x \in H\right\\}\).

A property of groups is said to be "preserved under homomorphism" if, whenever a group \(G\) has that property, every homomorphic image of \(G\) does also. In this exercise set, we will survey a few typical properties preserved under homomorphism. If \(f: G \rightarrow H\) is a homomorphism of \(G\) onto \(H\), prove each of the following: If \(G\) is abelian, then \(H\) is abelian.

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