Chapter 5: Problem 11
If \(z\) and \(\omega\) are two complex numbers such that \(|z \omega|=1\) and \(\arg (z)-\arg (\omega)=\frac{\pi}{2}\), then: \(\quad\) [April 10, 2019 (II)] (a) \(\bar{z} \omega=i\) (b) \(z \bar{\omega}=\frac{-1+i}{\sqrt{2}}\) (c) \(\bar{z} \omega=-i\) (d) \(\quad z \omega=\frac{1-i}{\sqrt{2}}\)
Short Answer
Step by step solution
Use the Property of Magnitudes for Complex Numbers
Use the Property of Arguments for Complex Numbers
Express in Polar Form
Find the Ratio \(z/\omega\)
Solve for \(z\) in terms of \(\omega\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Magnitude of Complex Numbers
Understanding magnitudes becomes crucial when dealing with multiplication of complex numbers. Given two complex numbers \(z\) and \(\omega\), the property \(|z\omega| = |z| \cdot |\omega|\) holds. This implies that the size, or "stretch," of the complex product is the product of the individual magnitudes.
In the exercise, we are provided that \(|z\omega| = 1\). Consequently, it implies \(|z| \cdot |\omega| = 1\), leading to the relation \(|z| = \frac{1}{|\omega|}\). This tells us one number is the reciprocal of the other's magnitude, thus balancing each other out to achieve the unit magnitude of 1.
Argument of Complex Numbers
When working with properties of arguments, it's critical to note that they transform under division as \(\text{arg}(z/\omega) = \text{arg}(z) - \text{arg}(\omega)\). In the given exercise, we stated that \(\arg(z) - \arg(\omega) = \frac{\pi}{2}\). This tells us that if we were to divide one complex number by another, the resulting complex number's direction is rotated by \(90^\circ\).
Having this understanding allows us to interpret complex numbers geometrically as rotations and scalings on the complex plane, aiding in solving algebraic complex problems in a more intuitive way.
Polar Form of Complex Numbers
In polar form, multiplication of complex numbers becomes straightforward because it involves multiplying magnitudes and adding angles. Specifically, if \(z = r_z e^{i\theta_z}\) and \(\omega = r_\omega e^{i\theta_\omega}\), then their product is given by \(z\omega = (r_z \cdot r_\omega) e^{i(\theta_z + \theta_\omega)}\).
For the exercise, using the polar form, we express that when dividing the complex numbers \(z/\omega = e^{i(\frac{\pi}{2})}\) results in \(i\). This provides clarity that \(z = i\omega\), allowing the angle between \(z\) and \(\omega\) to accurately reflect a \(90^\circ\) rotation.
Complex Number Multiplication
Remember, for basic rectangular form \(z = a + bi, \omega = c + di\), multiplication follows the distributive property: \(z\omega = (ac-bd) + (ad+bc)i\). However, it's often more elegant to multiply in polar form as mentioned, which streamlines your work by transforming algebraic manipulation into simple multiplications and sum of angles.
The provided exercise showcases the product \(z\omega\), underlined by the equation \([-i(|\omega|^2)\). The identity \(\bar{z} \omega = -i\) involves complex conjugates, ensuring a deeper understanding that multiplying by conjugates contracts the angle to the opposite quadrant of the circle, thus permitting a negative result in the imaginary axis as indicated by option (c). This aligns with the property \(|z\omega| = 1\), confirming the correctness of given solutions through this geometric perspective.