Chapter 25: Problem 67
Let \(\vec{a}=\hat{i}+\hat{j}+\hat{k}, \vec{c}=\hat{j}-\hat{k}\) and a vector \(\vec{b}\) be such that \(\vec{a} \times \vec{b}=\vec{c}\) and \(\vec{a} \cdot \vec{b}=3 .\) Then \(|\vec{b}|\) equals? [Online April 16, 2018] (a) \(\sqrt{\frac{11}{3}}\) (b) \(\frac{\sqrt{11}}{3}\) (c) \(\frac{11}{\sqrt{3}}\) (d) \(\frac{11}{3}\)
Short Answer
Step by step solution
Understanding Given Vectors
Writing Cross Product Equation
Solving Cross Product Equation
Solving Dot Product Equation
Calculate Magnitude of \(\vec{b}\)
Identify the Correct Answer Choice
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
- The result is a vector perpendicular to the plane containing \( \vec{a} \) and \( \vec{b} \).
- The operation is anti-commutative, meaning \( \vec{a} \times \vec{b} = - (\vec{b} \times \vec{a}) \).
- It is only defined in three dimensions.
Dot Product
- The dot product is a scalar quantity.
- It is commutative, which means \( \vec{a} \cdot \vec{b} = \vec{b} \cdot \vec{a} \).
- This operation is useful for determining the angle \( \theta \) between two vectors using the formula \( \cos(\theta) = \frac{\vec{a} \cdot \vec{b}}{\|\vec{a}\| \|\vec{b}\|} \).
Vector Magnitude
- It is always a non-negative scalar.
- The magnitude is akin to measuring the distance of the vector from the origin in the three-dimensional space.
- This measure forms the basis for normalizing a vector, which involves dividing each component by the magnitude to yield a unit vector.
JEE Mathematics
- Basic operations like addition, subtraction, and scalar multiplication.
- Vector products, which include both dot and cross products.
- Calculating magnitudes and directions of vectors.