Chapter 25: Problem 59
Let \(\vec{a}=\hat{i}-2 \hat{j}+\hat{k}\) and \(\vec{b}=\hat{i}-\hat{j}+\hat{k}\) be two vectors. If \(\vec{c}\) is a vector such that \(\vec{b} \times \vec{c}=\vec{b} \times \vec{a}\) and \(\vec{c} \cdot \vec{a}=0\), then \(\begin{array}{ll}\vec{c} \cdot \vec{b} \text { is equal to: } & \text { [Jan. 8, 2020 (II)] }\end{array}\) (a) \(-\frac{3}{2}\) (b) \(\frac{1}{2}\) (c) \(-\frac{1}{2}\) (d) \(-1\)
Short Answer
Step by step solution
Understanding the problem
Compute \( \vec{b} \times \vec{a} \)
Set \( \vec{b} \times \vec{c} = \vec{b} \times \vec{a} \)
Apply the dot product condition
Equation system for \( \vec{c} \)
Compute \( \vec{c} \cdot \vec{b} \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
Given vectors \( \vec{a} \) and \( \vec{b} \), the cross product \( \vec{a} \times \vec{b} \) is calculated using the determinant of a matrix with \( \hat{i}, \hat{j}, \hat{k} \) as the first row and the components of \( \vec{a} \) and \( \vec{b} \) as the second and third rows respectively. For example, if \( \vec{a} = a_1 \hat{i} + a_2 \hat{j} + a_3 \hat{k} \) and \( \vec{b} = b_1 \hat{i} + b_2 \hat{j} + b_3 \hat{k} \), the determinant is:\[\vec{a} \times \vec{b} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \ a_1 & a_2 & a_3 \ b_1 & b_2 & b_3 \end{vmatrix}\]
- Choose the sign of the result for each component carefully, based on the pattern of the determinant.
- The cross product is anti-commutative, meaning \( \vec{a} \times \vec{b} = - (\vec{b} \times \vec{a}) \).
Dot Product
For two vectors \( \vec{a} = a_1 \hat{i} + a_2 \hat{j} + a_3 \hat{k} \) and \( \vec{b} = b_1 \hat{i} + b_2 \hat{j} + b_3 \hat{k} \), the dot product is calculated as:\[\vec{a} \cdot \vec{b} = a_1b_1 + a_2b_2 + a_3b_3\] Here are some key characteristics:
- The dot product is commutative: \( \vec{a} \cdot \vec{b} = \vec{b} \cdot \vec{a} \).
- If the dot product is zero, the vectors are perpendicular (orthogonal).
- The dot product is used to calculate projections and angles between vectors.
Linear Combination
For instance, if you have vectors \( \vec{a} \), \( \vec{b} \), and \( \vec{c} \), a linear combination of these vectors is expressed as:\[x\vec{a} + y\vec{b} + z\vec{c}\] where \( x, y, \) and \( z \) are coefficients.
Here’s how it connects to other concepts:
- Linear combinations are foundational in determining vector span, bases, and dimension.
- Any vector within the span of \( \{\vec{a}, \vec{b}, \vec{c}\} \) can be expressed as a linear combination of these vectors.
- This concept is widely used in solving systems of linear equations, transformations, and more complex topics like eigenvectors and eigenvalues.
Perpendicular Vectors
Mathematically, for vectors \( \vec{a} \) and \( \vec{b} \), they are perpendicular if:\[ \vec{a} \cdot \vec{b} = 0 \] This orthogonality has several applications and implications:
- Perpendicular vectors often arise in coordinate systems, where axes are perpendicular by definition.
- They are critical in maximizing dot products where the vector directions need to be aligned perpendicularly for calculations like projections.
- Orthogonal vectors are important in constructing orthogonal bases, simplifying complex calculations in vector spaces.