Chapter 25: Problem 34
A vector \(\vec{a}=\alpha \hat{i}+2 \hat{j}+\beta \hat{k}(\alpha, \beta \in \boldsymbol{R})\) lies in the plane of the vectors, \(\vec{b}=\hat{i}+\hat{j}\) and \(\vec{c}=\hat{i}-\hat{j}+4 \hat{k}\). If \(\vec{a}\) bisects the angle between \(\vec{b}\) and \(\vec{c}\), then: [Jan. 7, 2020 (I)] (a) \(\vec{a} \cdot \hat{i}+3=0\) (b) \(\vec{a} \cdot \hat{i}+1=0\) (c) \(\vec{a} \cdot \hat{k}+2=0\) (d) \(\vec{a} \cdot \hat{k}+4=0\)
Short Answer
Step by step solution
Understand the Problem
Check Coplanarity Condition
Calculate Cross Product \(\vec{a} \times \vec{b}\)
Calculate \((\vec{a} \times \vec{b}) \cdot \vec{c}\)
Express Bisector Condition Algebraically
Sum Vectors \(\vec{b}\) and \(\vec{c}\)
Relate \(\vec{a}\) to \(2\hat{i} + 4\hat{k}\)
Solve for \(\alpha\) and \(\beta\) in Bisector
Final Step: Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Coplanarity
This condition is determined using the formula \((\vec{a} \times \vec{b}) \cdot \vec{c} = 0\). The cross product \(\vec{a} \times \vec{b}\) gives a vector perpendicular to both \(\vec{a}\) and \(\vec{b}\). When you dot this result with \(\vec{c}\), it should be zero if these vectors are coplanar.
- Cross product indicates a vector orthogonal to a given plane formed by two vectors.
- Dot product checks alignment or perpendicularity regarding this plane.
Cross Product
The cross product \(\vec{a} \times \vec{b}\) involves a determinant calculation, which can be visualized as:
\[ \vec{a} \times \vec{b} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \ \alpha & 2 & \beta \ 1 & 1 & 0 \end{vmatrix} \]
This operation is different from the dot product, which results in a scalar. Here, the result is another vector: \(-\beta \hat{j} - (\alpha + 2) \hat{k}\).
- Cross product calculations help identify perpendicular vectors and are vital in studying physics as related to torque and magnetic forces.
- The magnitude of a cross product reveals the area of the parallelogram formed by two vectors.
Angle Bisector
When \(\vec{a}\) bisects the angle between \(\vec{b}\) and \(\vec{c}\), it implies \(\vec{a}\) is proportional to the normalized sum of these vectors: \(\vec{a} = k(\vec{b} + \vec{c})\). With \(\vec{b} = \hat{i} + \hat{j}\) and \(\vec{c} = \hat{i} - \hat{j} + 4\hat{k}\), their sum simplifies to \(2\hat{i} + 4\hat{k}\).
By comparing, you get \(\alpha = 2k\) and \(\beta = 4k\), considering the conditions of the exercise we find that \(\alpha = -3\).
- An angle bisector ensures equal partitioning of two angles, exemplifying symmetry and balance in vector representation.
- Normalization of the vectors involved keeps the computations within concise numerical bounds.