Chapter 24: Problem 18
Let \(f:(0, \infty) \rightarrow(0, \infty)\) be a differentiable function such that \(f(1)=e\) and \(\lim _{t \rightarrow x} \frac{t^{2} f^{2}(x)-x^{2} f^{2}(t)}{t-x}=0\). If \(f(x)=1\), then \(x\) is equal to: \(\quad\) [Sep. 04, 2020 (II)] (a) \(\frac{1}{e}\) (b) \(2 e\) (c) \(\frac{1}{2 e}\) (d) \(e\)
Short Answer
Step by step solution
Analyze the given limit
Assume a solution form and check
Solve for given condition \(f(x)=1\)
Confirm the value of \(x\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limit Definition
In the given exercise, the limit given is \[\lim_{t \rightarrow x} \frac{t^{2} f^{2}(x) - x^{2} f^{2}(t)}{t-x} = 0.\]This resembles the definition of a derivative. The expression inside the limit indicates that as \(t\) approaches \(x\), the numerator approaches zero at a rate balanced by the denominator. Such a relation suggests that there is a certain symmetry or constancy in the function \(f\). Here, the limit helps identify that \(t^2 f^2(t)\) behaves like a constant, leading us to further exploration in the problem.
Derivative
- This indicates an element of differentiation, as this form suggests a derivative of some composite or transformed function.
- The outcome points to \(t^2 f^2(t)\) being a constant function of \(t\), as the derivative equaling zero suggests a lack of change.
Constant Function
- When we solve \(f^2(t) = \frac{C}{t^2}\), and use the given initial condition \(f(1) = e\), it simplifies to a straightforward form with \(C = e^2\).
- This reveals that the expression behaves as a constant with respect to \(t\), linking back to the nature of the derivative presented earlier.
Initial Condition
- It allows us to determine the constant \(C\) in the expression \(t^2 f^2(t) = C\).
- By substituting \(t = 1\) into \(f^2(t) = \frac{C}{t^2}\), we find \(C = e^2\), simplifying the function to \(f^2(t) = \frac{e^2}{t^2}\).