Chapter 21: Problem 68
If the tangent at a point \(\mathrm{P}\), with parameter \(\mathrm{t}\), on the curve \(\mathrm{x}=4 \mathrm{t}^{2}+3, \mathrm{y}=8 \mathrm{t}^{3}-1, \mathrm{t} \in \mathrm{R}\), meets the curve again at a point \(\mathrm{Q}\), then the coordinates of \(\mathrm{Q}\) are : [Online April 9, 2016] (a) \(\left(16 t^{2}+3,-64 t^{3}-1\right)\) (b) \(\left(4 t^{2}+3,-8 t^{3}-2\right)\) (c) \(\left(t^{2}+3, t^{3}-1\right)\) (d) \(\left(t^{2}+3,-t^{3}-1\right)\)
Short Answer
Step by step solution
Identify the curve equations
Find the derivative of the curve
Calculate the slope of the tangent at P
Equation of the tangent line
Rearrange the tangent equation
Substitute parametric equations into tangent
Solve for t' in relation to t
Substitute to find coordinates of Q
Determine coordinates of point Q
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