Chapter 20: Problem 64
If \(f(x)=\left\\{\begin{array}{ll}x e^{-\left(\frac{1}{|x|} \mid \frac{1}{x}\right)}, x \neq 0 \\ 0 & , x=0\end{array}\right.\) then \(\mathrm{f}(\mathrm{x})\) is (a) discontinuous every where (b) continuous as well as differentiable for all \(x\) (c) continuous for all \(x\) but not differentiable at \(x=0\) (d) neither differentiable nor continuous at \(x=0\)
Short Answer
Step by step solution
Analyze the function for points where \(x \neq 0\)
Analyze continuity at \(x = 0\)
Analyze differentiability at \(x = 0\)
Synthesize the findings
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Differentiability at a Point
- This is checked using the formula for the derivative:
Limit of a Function
- We substituted the function form given by \(x e^{-\left(\frac{1}{x}\right)}\) and then evaluated it as \(x\) approaches zero.
Discontinuity
- The limit \(\lim_{x \to 0} f(x)\) method was used to ascertain if there were breaks in continuity.
- Since \(\lim_{x \to 0} f(x) = f(0)\), this confirmed no discontinuity at \(x=0\). This ensures a smooth pass through that point on the graph.
Exponential Function
- This particular exponential expression significantly influences the behavior of the function even at boundary conditions, such as when \(x \to 0\).
- Its rapid decay means it approaches zero much faster than any polynomial or linear component might.