Chapter 18: Problem 23
Let \(A=\left(\begin{array}{ccc}0 & 2 \mathrm{q} & r \\ p & q & -r \\ p & -q & r\end{array}\right)\). If \(\mathrm{AA}^{\mathrm{T}}=\mathrm{I}_{3}\), then \(|\mathrm{p}|\) is : [Jan. 11, 2019 (I)] (a) \(\frac{1}{\sqrt{5}}\) (b) \(\frac{1}{\sqrt{3}}\) (c) \(\frac{1}{\sqrt{2}}\) (d) \(\frac{1}{\sqrt{6}}\)
Short Answer
Step by step solution
Understand the Problem
Multiply Matrices A and A^T
Compute Each Element of AA^T
Set AA^T Equal to I₃ and Solve
Solve for |p|
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Matrix Multiplication
Here's a step-by-step guide on performing matrix multiplication:
- Take the elements in the row of the first matrix.
- Multiply them by the corresponding elements in the column of the second matrix.
- Add the products to get a single number, which is the entry in the resultant matrix.
In the problem we've worked on, you're asked to multiply matrix A by its transpose, AT. This multiplication is crucial in finding whether a matrix is orthogonal when its product with its transpose equals the Identity Matrix.
Identity Matrix
An identity matrix has ones on its main diagonal (from the top-left to the bottom-right) and zeros elsewhere. For a 3x3 identity matrix, denoted as I3, it looks like this:
- \[ I_3 = \begin{pmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1 \end{pmatrix} \]
In this exercise, the goal was to show that multiplying matrix A with its transpose results in the identity matrix, affirming that A is orthogonal. This property helps verify calculations and equipped us to solve for the specific terms that give A its orthogonality.
Matrix Transpose
For a given matrix A:
- The first row becomes the first column of AT.
- The second row becomes the second column, and so forth.
Mathematically, if A is a matrix represented by \[ A = \begin{pmatrix} a & b \ c & d \end{pmatrix}, \] its transpose, AT, will be \[ A^T = \begin{pmatrix} a & c \ b & d \end{pmatrix}. \] Transposing was an essential step in our problem when verifying that A multiplied by AT equals the identity matrix.
Magnitude of a Number
To determine the magnitude, represented as \(|a|\), simply consider a:
- If a is positive or zero, |a| is a itself.
- If a is negative, |a| is -a (the opposite number, which is positive).
In the problem at hand, we found the magnitude of the component \(|p|\) by solving the equation derived from making the matrix product equal to the identity matrix. The importance of magnitude here is that it provides a positive length of the vector, which was \[ |p| = \frac{1}{\sqrt{2}}. \] This indicates that no matter whether p is positive or negative, its absolute size is critical in maintaining orthogonality in the matrix.