Chapter 15: Problem 8
A number \(x\) is chosen at random from the set \(\\{1,2,3,4, \ldots .\), 100\\}. Define the event: \(\mathrm{A}=\) the chosen number \(\mathrm{x}\) satisfies \(\frac{(x-10)(x-50)}{(x-30)} \geq 0\) Then \(\mathrm{P}(\mathrm{A})\) is: \(\quad[\) Online April 12, 2014] (a) \(0.71\) (b) \(0.70\) (c) \(0.51\) (d) \(0.20\)
Short Answer
Step by step solution
Analyze the Inequality
Test Each Interval
Include Critical Points
List Satisfying Values
Calculate the Probability
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Inequalities
- The numerator \((x-10)(x-50)\) will be positive or zero when \(x\) is exactly 10 or 50, and positive in between or beyond these points if the same factor combination provides a positive product.
- The expression \(\frac{1}{x-30}\) creates a vertical asymptote at \(x=30\), where the entire fraction is undefined.
Number Line Test
With the given inequality \( \frac{(x-10)(x-50)}{(x-30)} \geq 0 \), we identify critical points at \(x=10\), \(x=30\), and \(x=50\). These points divide the number line into four sections:
- \((1, 10)\)
- \((10, 30)\)
- \((30, 50)\)
- \((50, 100)\)
Critical Points
- Set \(x-10 = 0\), so \(x = 10\). This is where the numerator is zero.
- Set \(x-50 = 0\), so \(x = 50\). Again, the numerator is zero here.
- Set \(x-30 = 0\), so \(x = 30\). This makes the denominator zero, creating a vertical asymptote, and thus the expression is undefined here.
Intervals
For this exercise, the intervals are \((1,10)\), \((10,30)\), \((30,50)\), and \((50,100)\). Each of these intervals represents a segment of values for \(x\) where we test our inequality:
- In \((1,10)\), the inequality holds.
- In \((10,30)\), the inequality holds.
- In \((30,50)\), the inequality does not hold.
- In \((50,100)\), the inequality holds.